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Bezzdna [24]
3 years ago
6

In which atmosphere layer do humans live most of their life

Chemistry
1 answer:
marysya [2.9K]3 years ago
3 0
Troposphere, this is the layer of the atmosphere closest to the earths crust.
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Relation between glancing and angle of deviation<br>​
shtirl [24]

Answer:

the Glancing angle is the angle between the incident ray and plane mirror which is 90o in the given case. The angle between the direction of the incident ray and the reflected ray is the angle of deviation. Since the angle of deviation for a plane mirror is twice the glancing angle, the angle of deviation is 1800.

5 0
3 years ago
Determine the [OH−] , Ph, and POH of a solution with a [H+] of 0. 00017 m at 25 °C.
tino4ka555 [31]

Main Answer:

Given

pH = -log[H+]

= -log[0.00017]

= 3.769

We know that

pW = pH + pOH

and pW =14

pOH = 14-pH

=14-3.769

=10.231

According to the definition

pOH = -log[OH-]

10.231 = log[OH-]-1

[OH-]= 5.87 x 10-11

Explanation:

What is pH?

pH is defined as the concentration of H+ ion in the solution. If the pH value is less than 7, then the solution will be acidic. If the pH value is greater than 7, then the solution will be basic.

To know more about pH, please visit:

brainly.com/question/8758541

#SPJ4

4 0
2 years ago
If a stone with an original velocity of 0 is falling from a ledge and takes 8 seconds to hit the ground what is the final veloci
ziro4ka [17]
Also 0 as it hits the ground and stops
5 0
3 years ago
What are the products of photosynthesis
spin [16.1K]
Oxygen (6O2) and Glucose (C6H12O6)

<span>Reference: 6CO2 + 6H2O + light energy = C6H12O6 + 6O2.</span>
3 0
3 years ago
Read 2 more answers
or a particular isomer of C 8 H 18 , the combustion reaction produces 5104.1 kJ of heat per mole of C 8 H 18 ( g ) consumed, und
beks73 [17]

Answer:

The standard enthalpy of formation of this isomer of C_{8}H_{18} is -220.1 kJ/mol.

Explanation:

The given chemical reaction is as follows.

C_{8}H_{18}(g)+ \frac{25}{2}O_{2}(g) \rightarrow 8CO_{2}(g)+9H_{2}O(g)

\Delta H^{o}_{rxn}= -5104.1kJ/mol

The expression for the entropy change for the reaction is as follows.

\Delta H^{o}_{rxn}=[8\Delta H^{o}_{f}(CO_{2}) +9\Delta H^{o}_{f}(H_{2}O)]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}\Delta H^{o}_{f}(O_{2})]

\Delta H^{o}_{f}(H_{2}O)= -241.8kJ/mol

\Delta H^{o}_{f}(CO_{2})= -393.5kJ/mol

\Delta H^{o}_{f}(O_{2})= 0kJ/mol

Substitute the all values in the entropy change expression.

-5104.1kJ/mol=[8(-393.5)+9(-241.8)kJ/mol]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}(0)kJ/mol]

-5104.1kJ/mol=-5324.2kJ/mol -\Delta H^{o}_{f}(C_{8}H_{18})

\Delta H^{o}_{f}(C_{8}H_{18}) =-5324.2kJ/mol +5104.1kJ/mol

=-220.1kJ/mol

Therefore, The standard enthalpy of formation of this isomer of C_{8}H_{18} is -220.1 kJ/mol.

4 0
3 years ago
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