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vodka [1.7K]
3 years ago
14

A company with loud machinery needs to cut its sound intensity to 44% of its original level. By how many decibels would the loud

ness be reduced? Use the formula L=10log I/I(o). Round to the nearest hundredth.
A) 3.57 decibels
B) 1.58 decibels
C) 2.52 decibels
D) 1.93 decibels
Mathematics
2 answers:
salantis [7]3 years ago
7 0
C.2.52 is your answer
Naddik [55]3 years ago
4 0

1) log_8a-log_82

2) 2.089

3) 3.57 decibels

4) 0.82

5) 41.67

6) In x^2/c^5

7) 21,405 mowers

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Liono4ka [1.6K]

6 + (10 - 4)2 - 20 = 6 + 12 - 20 = 18 - 20 = -2

Assuming that the two in the middle of the expression is multiplied by (10 - x) the answer would be -2. I apologize if I did not read your question right.

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A square is a type of quadrilateral. 
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If 3x + 2y = 8 and x is twice the value of y, what is the value of x<br> -y?
Galina-37 [17]

Answer:

1

Step-by-step explanation:

3x+2y=8          

x=2y

3(2y)+2y=8

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A drug company is considering marketing a new local anesthetic. The effective time of the anesthetic the drug company is current
lapo4ka [179]

Using the z-distribution, we have that:

a)

The hypothesis test is:

  • H_0: \mu = 7.4
  • H_1: \mu < 7.4

The p-value is of 0.0668.

The critical value is z^{\ast} = -1.28

b) Since the <u>test statistic is less than the critical value</u> for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.

Item a:

At the null hypothesis, it is <u>tested if the mean is of 7.4 minutes</u>, that is:

H_0: \mu = 7.4

At the alternative hypothesis, it is <u>tested if the mean is lower than 7.4 minutes</u>, that is:

H_1: \mu < 7.4

We have the <u>standard deviation for the population</u>, hence, the z-distribution is used.

The test statistic is given by:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • \sigma is the standard deviation of the sample.
  • n is the sample size.

For this problem, the values of the <em>parameters </em>are: \overline{x} = 7.1, \mu = 7.4, \sigma = 1.2, n = 36.

Hence, the value of the <em>test statistic</em> is:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{7.1 - 7.4}{\frac{1.2}{\sqrt{36}}}

z = -1.5

Using a z-distribution calculator, the p-value is of 0.0668.

Also using a calculator, considering a <u>left-tailed test</u>, as we are testing if the mean is less than a value, the critical value with a <u>significance level of 0.1</u> is of z^{\ast} = -1.28.

Item b:

Since the <u>test statistic is less than the critical value</u> for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.

You can learn more about the use of the z-distribution to test an hypothesis at brainly.com/question/16313918

5 0
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What is the value of m in the equation 5m − 7 = 6m 11? 18 1 −18 −1.
denpristay [2]

Answer:

-7 = m

Step-by-step explanation:

5m − 7 = 6m

Subtract 5m from each side

5m-5m − 7 = 6m-5m

-7 = m

6 0
2 years ago
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