Difference of 2 perfec squares is
(a^2)-(b^2)
if the exponents are both even and the coeficient (the number in front) are perfect squares, then it is difference t 2 perfect squares
first one
8 is not perfect square
2nd one
(4e^4)^2-(9g^2)^2
third
25 is odd, so it cannot be split up into 2 nice numbers
4th
(11m^9)^2-(3n^5)^2
Answer:
3500$
Step-by-step explanation:
3800÷2-600=1300$
Answer:
-3x² +6x -1 = 0
Step-by-step explanation:
x2 - 2x + = 4(x2-2x +1)-3
x² - 2x = 4x²-8x +4 - 3
x²-4x²-2x+8x = 4-3
-3x² +6x = 1
-3x² +6x -1 = 0