- y - 10 = 6x 5x + y = - 10

Mathematics

1 answer:

Inga [223]3 years ago

5 0

Answer:

(0,-10)

Step-by-step explanation:

not to sure if this is what your asking for, sorry

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-2x^(3) +3=-1x^(3) -1x^(2) +1x+1

Natali5045456 [20]

-2x³ + 3 = -x³ - x² + x + 1

Add x³ to both sides, and subtract 3 from both sides.

-2x³ + x³ = -x² + x + 1 - 3

Add like terms.

-x³ = -x²+ x - 2

Move all of the (X's) to both sides, by adding x² to both sides, and subtracting x form both sides.

-x³ + x² - x = -2

~Hope I helped!~

7 0

3 years ago

what is the y-intercept of the line perpendicular to the line y=-3/4x+5 that includes the point (-3,-3)?

Deffense [45]

Answer:

Step-by-step explanation:

For this question, your friend is the point-slope form.

Point-slope form = $y-y_1 = m(x-x_1)$

The only variables you replace are m = slope, y1 = y of a given point, and x1 = x of a given point.

First, we need to find the slope that is perpendicular to the equation $y=-\frac{3}{4}x+5$

An equation that is perpendicular to another equation have to be negative reciprocals (negative inverse) of each other.

If the slope is 3, then the negative reciprocal of 3 is $-\frac{1}{3}$ .

So, since the given slope is -3/4, the negative reciprocal is $\frac{4}{3}$ .

We will use the negative reciprocal as m since we are trying to find the equation of line that includes (-3, -3) and is perpendicular to the other equation.

We will use point slope form using the (-3, -3) points and negative reciprocal as m.

$y-y_1 = m(x-x_1)\\y-(-3) = \frac{4}{3} (x-(-3))\\y+3=\frac{4}{3}(x+3)$

Now, we need to convert this into slope-intercept form. The reason why we need to do this is because y = mx + b, where b is the y-intercept. To do this, solve for y - or in other words, isolate y..

$y+3=\frac{4}{3}(x+3)\\y+3=\frac{4x}{3}+4\\y+3-3=\frac{4x}{3}+4-3\\y=\frac{4}{3}x+1$