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Troyanec [42]
3 years ago
9

8 men will take 10 days to build a wall 150 metres long. After the men had started working for 6 days, they were told that the w

all needed to by lengthened by 45 metres. How many more men must be hired to complete the job on time?​
Mathematics
1 answer:
Mashutka [201]3 years ago
3 0
First, find out how much each man works. If eight men take 10 days to build 150 m of wall, then that means that it takes 80 man days to build 150 m. One Man day is then 150÷80, in other words 1.875. If eight men have already been working for six days, then they have spent 8×6 man days, 48. 48 men days times 1.875 m of wall per man day equals 90 m of wall have been built. So, you have four days left to build the remaining 60 m of wall as well as 45 extra meters, in other words, 105 m total. 105 m divided by four days equals 26.25 m need to be built every day. Since one man builds 1.875 m of wall every day, to find the number of men total you need for the last four days, take 26.25÷1.875, Which equals 14 exactly. 14 is not the answer however, because it’s asking how many more men you need. Since you already have eight, you need six more to make 14

The answer is six more men
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Plz help me with this
saul85 [17]

Your answer would be the second option, (-4,5).

We can find this by substituting in each point into the equation y < |x - 3| and seeing if it is true.

For the first one you get 1 < |2 - 1|. |2 - 1| = |-1| = 1, and 1 cannot be less than itself, so this is false.

For the second one you get 5 < |-4 - 3|. |-4 - 3| = |-7| = 7, and 5 is indeed less than 7, so this is correct.

I hope this helps!

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3 years ago
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After page 182 in a book came page 187. How many pages were missing ?
WITCHER [35]
5 pages because 187-182=5
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3 years ago
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PLEASE HELP ILL MARK BRAINLIEST !!!
Alexus [3.1K]

Answer:

a) the common difference is 20

b) x_8=115 , x_{12}=195

c) the common difference is -13

d) a_{12}=52, a_{15}=13

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: x_n=x_1+(n-1)d

We know common difference d= 20, we need to find x_1

Using x_3=16 we can find x_1

x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25

So, We have x_1 = -25

Now finding x_8

x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115

So, \mathbf{x_8=115}

Now finding x_{12}

x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195

So, \mathbf{x_{12}=195}

c) what is the common difference of the sequence a_m

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: a_n=a_1+(n-1)d

We know common difference d= -13, we need to find a_1

Using a_7=104 we can find x_1

a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195

So, We have a_1 = 195

Now finding a_{12} , put n=12

a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52

So, \mathbf{a_{12}=52}

Now finding a_{15} , put n=15

a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13

So, \mathbf{a_{15}=13}

5 0
3 years ago
griffin ordered a pair of sneakers online. he had 16 credit that he applied toward the purchase, and then he used a credit card
Doss [256]

Answer: Griffin charge $79.854 to his credit card when he bought the sneakers.

Step-by-step explanation:

Griffin ordered a pair of sneakers online.

Value of each credit point = 1 cent

Then , value of 16 credit points = 16 cents = $0.16 [1$ = 100 cents]

Cost of shoes = Rs $80

Charge to credit card = (Cost of shoes) - (Value of 16 credit points)

= $(80-0.16)

= $79.84

Hence, Griffin charge $79.854 to his credit card when he bought the sneakers.

4 0
4 years ago
Acrosonic's production department estimates that the total cost (in dollars) incurred in manufacturing x ElectroStat speaker sys
il63 [147K]

Answer:

a)  P(x)=-0.042x^2+530x-18000

b)  P'(x)=-0.084x+530

c)

P'(4000)=194

P'(9500)=-268

Step-by-step explanation:

a)

We know that Revenue is our total income and cost is our total cost. Thus, profit is what's left after cost is subtracted from Income (revenue). Thus, we can say:

P(x) = R(x) - C(x)

Finding Profit Function (P(x)):

P(x) = R(x) - C(x)\\P(x) = -0.042x^2+800x-(270x+18000)\\P(x)=-0.042x^2+800x-270x-18000\\P(x)=-0.042x^2+530x-18000

This is the profit function.

b)

The marginal profit is the profit earned when ONE ADDITIONAL UNIT of the product is sold. This is basically the rate of change of profit per unit. We find this by finding the DERIVATIVE of the Profit Function.

Remember the power rule for differentiation shown below:

\frac{d}{dx}(x^n)=nx^{n-1}

Now, we differentiate the profit function to get the marginal profit function (P'):

P(x)=-0.042x^2+530x-18000\\P'(x)=2(-0.042)x^1+530x^0-0\\P'(x)=-0.084x+530

This is the marginal profit function , P'.

c)

We need to find P'(4000) and P'(9500). So we basically put "4000" and "9500" in the marginal profit function's "x". The value is shown below:

P'(x)=-0.084x+530\\P'(4000)=-0.084(4000)+530\\P'(4000)=194

and

P'(x)=-0.084x+530\\P'(9500)=-0.084(9500)+530\\P'(9500)=-268

6 0
3 years ago
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