Answer:
Progenies of batch I would not be labeled by 35S; progenies of batch II would be labeled by 32P.
Explanation:
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B. At high temperatures, the active site of the enzyme is damaged and it is no longer able to attack itself to the required substrate as its shape will no longer match.
After the 1st half-life 250 g of the radioactive material will be left.
<span>After the 2nd half-life 125 g of the radioactive material will be left. </span>
<span>After the 3rd half-life 62.5 g of the radioactive material will be left. </span>
<span>Therefore after 60 minutes, 3 half lives would have occurred. </span>
<span>Therefore the half-life = 60 / 3 = 20 minutes when 250 grams of the original material would have remained radioactive. </span>
<span>Therefore the answer is A) About 250 gram of the material decayed in 20 minutes.</span>
In my opinion the best sounding answer is C I hope this helpes<span />
