The Given equation is , 3 x + x = 440,
Let speed of train A is x Km/hour and Speed of train B which is a Bullet train which starts from same station but from different platform is 3 times the speed of train A.
And Sum of their Velocities is i.e Velocity of train A and Velocity of train B is 440 Km/hour.
4a + 3 = 15
- 3
4a = 12
÷ 4
a = 3
I hope this helps!
Answer: x = 4
Step-by-step explanation: To solve this equation, we could go right to our steps of subtracting 5.4 from both sides, but I would do a slightly different approach.
Since I hate working with decimals, I would get rid of them.
We can do this by multiplying both sides of the equation by 10, and remember to multiply every term by 10 to keep it balanced.
*Multiplying by 10 shifts the decimal point 1 place to the right
So we have 35x + 54 = 194 which looks a lot better.
Now subtract 54 from both sides to get 35x = 140.
Now divide both sides by 35 and x = 4.
Answer:
Answer for b is BFC and CFD
Answer for c is BFD and BFA
Answer for d is BFD and AFE
I don't know about a sorry
D
using the double - angle identity
cos (2A) = cos² A - sin² A = 2cos² A - 1 = 1 - 2sin² A
the right side = 1 - 2sin² (112.5° ) with A = 22.5°
hence 2A = 2 × 22.5° = 45°
thus cos 45° = 1 - 2sin² ( 22.5°)
