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3 years ago

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IF the area of the frame was 64inches², what would be 2 possible sets of dimensions that could be used to make a frame with that

area? Set 1: Set 2: Explain your thinking:

1 answer:

ValentinkaMS [17]3 years ago

5 0

5in=6 7in=5 would be

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Write the following inequality. You are not solving it, just writing it.

igomit [66]

Answer:

1. 350 + 25x = 35x + 200

2. 35x - 350 = 25x - 200

3. 350 - 35x = 200 + 25x

4. 200x - 350 = 25 + 35x

Step-by-step explanation:

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3 years ago

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What is a possible number greater than or equal to 7?

BARSIC [14]

Answer:

8,7,11,7.5,10000 any number that is 7, or bigger!

Step-by-step explanation:

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3 years ago

The area of a rectangle is 54 m2 , and the length of the rectangle is 3 m more than twice the width. find the dimensions of the

Elina [12.6K]

L = 3 + 2w

Find the width
Area = 54
l × w = 54
(3 + 2w) × w = 54
3w + 2w^2 = 54
2w^2 + 3w - 54 = 0
(2w - 9)(w + 6) = 0
w = 9/2 or w = -6 (width shouldn't be negative)
w = 9/2
w = 4.5 m

Find the length
l = 3 + 2w
l = 3 + 2(4.5)
l = 3 + 9
l = 12 m

The width is 4.5 m, the length is 12 m

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4 years ago

42x+45=56z<br> 43x+56=34z

Alecsey [184]

Question ? There is no question to help

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3 years ago

What is the common ratio of 2, 10/3, 50/9

mojhsa [17]

The common ratio of 2, 10/3, 50/9 is $\frac{10}{6}$

<u>Solution:</u>

Given, series of elements are $2, \frac{10}{3}, \frac{50}{9}$

We have to find the common ratio of the above given series.

We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.

So, now take $\frac{10}{3}$ and 2

$\text { Then, common ratio }=\frac{\frac{10}{3}}{2}$

$\begin{array}{l}{\text { Common ratio }=\frac{10}{3} \times \frac{1}{2}} \\\\ {\text { Common ratio }=\frac{10}{3 \times 2}=\frac{10}{6}}\end{array}$

Hence, the common ratio of the given series is $\frac{10}{6}$

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3 years ago