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Artemon [7]
3 years ago
11

Computers and other technologies perform a great deal of work today, reducing the need for workers with special expertise. As a

result, high-paying positions have been replaced with low-paying positions. This process has been termed __________.
Computers and Technology
1 answer:
Veronika [31]3 years ago
5 0

Answer: deskilling

Explanation: Deskilling is the process by which skilled labor within an industry or economy is abolished by the introduction of technologies operated by semi skilled or unskilled labourers .

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Which person would be the best fit for a career in the Information Technology field?
zaharov [31]
The best possible fit would be a person with a creative mind and flexible mind. 
The technical stuff can be taught and learnt. But to evolve and keep up with the pace of how technology improves day to day, you'd need some with flexibility to cope up with this and creativeness to make innovations.
6 0
3 years ago
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cout << "Part 1" << endl; // Part 1 // Enter the statement to print the numbers in index 4 and index 9 // put a spac
Margarita [4]

Answer and Explanation:

#include <iostream>

using namespace std;

int printEven(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2==0)

{

count++;

cout<<array[i]<<" ";

}

}

return count;

}

void printAll(int array[],int n)

{

for(int i=0;i<n;i++)

{

cout<<array[i]<<" ";

}

}

int computeTotalOdds(int array[],int n)

{

int count=0;

for(int i=0;i<n;i++)

{

if(array[i]%2!=0)

{

count++;

 

}

}

return count;

}

int main()

{

int array1[20] = {3, 18, 1, 25, 4, 7, 30, 9, 80, 16, 17};

int numElements = 11;

cout << "Part 1" << endl;

cout<<array1[4]<<" "<<array1[9];

cout << endl;

cout<<array1[0]<<" "<<array1[8];

cout << endl;

array1[2]=12;

cout << "\nPart 2" << endl;

printAll(array1,numElements);

 

cout << "\nPart 3" << endl;

int evens;

evens=printEven(array1,numElements);

 

 

 

 

// This will print the number of evens in the array.

cout << endl << evens;

 

cout << "\nPart 4" << endl;

 

int total;

 

total=computeTotalOdds(array1,numElements);

cout << endl << total;

 

return 0;

}

3 0
3 years ago
Learning in a digital environment is also called [blank] learning.
Dafna1 [17]

Answer:

The blank is online learning

4 0
3 years ago
Read 2 more answers
The following code accomplishes which of the tasks written below? Assume list is an int array that stores positive int values on
worty [1.4K]

Answer:

it stores the largest value in list (the maximum) in foo

Explanation:

Initially foo is assigned as the first element of the list

Inside the loop, every element in the list will be compared with foo, starting from the second element. If an element is greater than foo, the new value of the foo will be that element. At the end of the loop, foo will be equal to the largest element in the list.

5 0
3 years ago
How is the OR (||) logical operator used?<br> PLS HURRY
3241004551 [841]

Answer:

The answer is below

Explanation:

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4 0
3 years ago
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