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VikaD [51]
3 years ago
9

Help with 6 and 7 I rlly need help

Mathematics
1 answer:
n200080 [17]3 years ago
7 0

Answer:

6) 295.2 feet squared. 7) 2, 4, 7, 8

Step-by-step explanation:

6)

a = 16.4 \times 18

a = 295.2

7)

728 \div 2 = 364

728 \div 4 = 182

728 \div 7 = 104

728  \div 8 = 91

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Identify the measure of PR in the diagram. PLEASE HELP!!
kykrilka [37]

Answer:

The correct answer is :  Fourth, PR = 6

Step-by-step explanation:

PR is mid segment ( median line) of the side YZ in the triangle XYZ and is equal it's half.

PR = 1/2 YZ = 1/2 · 12 = 6

PR = 6

God with you!!!

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Rewrite 40 1/4 as a decimal
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40.25 is 40 1/4 as a decimal
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Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.
fenix001 [56]

Answer:

The angle between vector \vec{u} = 5\, \vec{i} - 8\, \vec{j} and \vec{v} = 5\, \vec{i} + \, \vec{j} is approximately 1.21 radians, which is equivalent to approximately 69.3^\circ.

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

  • their dot products, and
  • the product of their lengths.

To be precise, if \theta denotes the angle between \vec{u} and \vec{v} (assume that 0^\circ \le \theta < 180^\circ or equivalently 0 \le \theta < \pi,) then:

\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}.

<h3>Dot product of the two vectors</h3>

The first component of \vec{u} is 5 and the first component of \vec{v} is also

The second component of \vec{u} is (-8) while the second component of \vec{v} is 1. The product of these two second components is (-8) \times 1= (-8).

The dot product of \vec{u} and \vec{v} will thus be:

\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}.

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both \vec{u} and \vec{v}:

  • \| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}.
  • \| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}.

<h3>Angle between the two vectors</h3>

Let \theta represent the angle between \vec{u} and \vec{v}. Apply the formula\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} to find the cosine of this angle:

\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}.

Since \theta is the angle between two vectors, its value should be between 0\; \rm radians and \pi \; \rm radians (0^\circ and 180^\circ.) That is: 0 \le \theta < \pi and 0^\circ \le \theta < 180^\circ. Apply the arccosine function (the inverse of the cosine function) to find the value of \theta:

\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ .

3 0
3 years ago
What conditions must hold for a probability distribution to be acceptable?
VashaNatasha [74]

A distribution of probabilities is a numerical means of describing all unique combinations and the probabilities for a provided random variable, and the further discussion can be defined as follows:

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Therefore, the final choice is "Option A".

Learn more:

brainly.com/question/15848153

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