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2 years ago

15

Can someone solve this for me plsss i really need help with this no links an dno doing it just for the points need all three que

stions WILL GIVE BRAINLIEST

1 answer:

guajiro [1.7K]2 years ago

6 0

The first one is A and then the next one I believe should be 210 for both

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Type the correct answer in the box. Spell the word correctly.

Wittaler [7]

Answer:

Scarce demand / inflation

The word "scarce" means low on supplies or anything else.

Inflation is the term used when a price increases in the market.

These two terms together would best describe the higher demand.

Hope this helps, have a great day! ♥

7 0

2 years ago

Determine the x-intercepts of the function. Check all that apply. (–2, 0) (–1, –2) (0, 0) (1, 0) (2, 0)

blagie [28]

it's (0, 0) and (-2, 0) so A & C

8 0

3 years ago

Read 2 more answers

100 points, put nonsense, get reported. Susan wants to build a floor to put at the bottom of her tree house. She made the scale

Elanso [62]

Divide the length of the scale drawing by the scale (2.5) then multiply that by the scale feet (3)

11 inches / 2.5 = 4.4

4.4 x 3 = 13.2 feet

Answer: 13.2 feet

3 0

2 years ago

Read 2 more answers

The half-life of plutonium-241 is 14.4 years. How much of the original 3.6 grams of this

avanturin [10]

$\textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &3.6\\ t=\textit{elapsed time}\dotfill &45\\ h=\textit{half-life}\dotfill &14.4 \end{cases} \\\\\\ A=3.6\left( \frac{1}{2} \right)^{\frac{45}{14.4}}\implies A=3.6\left( \frac{1}{2} \right)^{3.125}\implies A\approx 0.41265$

5 0

2 years ago

The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor

nadya68 [22]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.05$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can use as an estimator for p $\hat p =0.5$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

3 0

3 years ago