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3 years ago

The equation y = 4.75x + 20 gives the cost y of towing a car if the car is towed x miles. Which statement is true?

1 answer:

5 0

The correct answer is C. For every mile the car is towed, the cost increases by $4.75.
Because for every mile the cost increases be $4.75.

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there are 32 ounces of water in a glass.Someone drinks 40% of the water how many ounces of water is left?

kherson [118]

If they drank 40%, then there are (100 - 40) = 60% still in the glass.

60% of 32 ounces = 0.6 x 32 = 19.2 ounces .

3 0

3 years ago

Which equation correctly relates kinetic energy, mass, and velocity?

juin [17]

Answer:

B, because the equation of kinetic energy is = mv²

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2 years ago

How many squares with sides that are 6 inches long are needed to cover a square with a side length of 30 inches without overlapp

ladessa [460]

5 squares are needed

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3 years ago

7. A, B, C, and D are positive integers. A,B,C forms an arithmetic sequence while B, C, D forms a

Stella [2.4K]

<u>Complete Question</u>

The positive integers A, B, and C form an arithmetic sequence while the integers B, C, and D form a geometric sequence. If (C/B) = (5/3), what is the smallest possible value of A + B + C + D?

Answer:

Step-by-step explanation:

If A, B, and C form an arithmetic progression

Their arithmetic mean, $B=\dfrac{A+C}{2}$

2B=A+C

C= 2B-A

B, C, D forms a geometric sequence and Common ratio, r=C/B=5/3

The terms in the geometric sequence are:

$B, B(\frac{5}{3} ), B(\frac{5}{3} )^2=B, \frac{5B}{3} , \frac{25B}{9}$

Therefore:

$C=\frac{5B}{3}\\D= \frac{25B}{9}$

So:

$A, B, C, D=A, B, \frac{5B}{3} , \frac{25B}{9}$

From arithmetic sequence

Common difference, $d=B - A = \frac{5B}{3} - B$

$2B -\frac{5B}{3}=A$

$(2 -\frac{5}{3})B=A\\(\frac{1}{3})B=A\\A=\frac{B}{3}\\$

$A, B,C, D =\frac{B}{3},\;B, \;\frac{5B}{3},\;\frac{25B}{9}$

These all have to be positive integers so B must be a multiple of 9, The smallest values are if B is 9

A,B,C,D=3,9,15,25

So the smallest possible value for:

A+B+C+D = 3+9+15+25 = 52

3 0

2 years ago

Val needs to find the area enclosed by the figure. The figure is made by attaching

jolli1 [7]

Answer: See below

Step-by-step explanation:

Radius of the semicircle = 46/2 = 23 m

$\therefore$ Area enclosed by the figure $=4 \times$ Area of semicircles + Area of square \begin{aligned} \\&=4 \times 3.14 \times(23)^{2} \times \frac{1}{2}+(46)^{2} \\&=3322.12+2116 \end{aligned} \\\\\\Area enclosed $=5438.12 \mathrm{~m}^{2}$$

So, Val might have have subtracted 2116 from 3322.12 instead of adding since 3322.12 - 2116 = 1206.12

3 0

1 year ago