The equation y = 4.75x + 20 gives the cost y of towing a car if the car is towed x miles. Which statement is true?

1 answer:

5 0

The correct answer is C. For every mile the car is towed, the cost increases by $4.75.
Because for every mile the cost increases be $4.75.

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garri49 [273]

Answer: c and e
explanation: put the equation in the graphing calculator and look at the graph and table the answer will show

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3 years ago

Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

$b^{91}\equiv2^{91}\pmod7$

$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
$8\equiv1\pmod7$
$2\equiv2\pmod7$
$\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7$

$c^{27}\equiv6^{27}\pmod7$

$6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7$

$\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7$

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3 years ago

WILL GIVE BRAINLIEST

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

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3 years ago

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Can you think of any 2x2 matrices d for which cd = dc for all 2x2 matrices c? give 2 different examples of such matricesd.

Ksju [112]

For any arbitrary 2x2 matrices $\mathbf C$ and $\mathbf D$ , only one choice of $\mathbf D$ exists to satisfy $\mathbf{CD}=\mathbf{DC}$ , which is the identity matrix.

There is no other matrix that would work unless we place some more restrictions on $\mathbf C$ . One such restriction would be to ensure that $\mathbf C$ is not singular, or its determinant is non-zero. Then this matrix has an inverse, and taking $\mathbf D=\mathbf C^{-1}$ we'd get equality.

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3 years ago

Will give Brainliest! if right!

Ilya [14]

<span>46, 37, 16, 24, 47, 23, 19, 31, 25

put in order</span>
16, 19, 23, 24, 25, 31,37, 46, 47

mean = 25

LOWER QUARTILE = (16+ 19+ 23+ 24) / 4 = 20.5

answer
Lower IQR = 20.5

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3 years ago

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