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pochemuha
3 years ago
15

Expand and simplify (y-3)³​

Mathematics
1 answer:
Tanya [424]3 years ago
5 0

Answer:

Expanded: (y-3)(y-3)(y-3)

Simplified:  y^{3}-9y^{2}+27y-27

Step-by-step explanation:

Expanded: (y-3)(y-3)(y-3)

Simplified:

y^{2} -3y-3y+9(y-3)\\y^{2} -6y+9(y-3)

y^{3} -3y^{2}-6y^{2}  +18y+9y-27

y^{3}-9y^{2} +27y-27

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Each sales associate at an electronics store has a choice of the two salary option shown below: 115 per week plus 9.5% commissio
Annette [7]
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5 0
3 years ago
In circle M with m \angle LMN= 98m∠LMN=98 and LM=18LM=18 units, find the length of arc LN. Round to the nearest hundredth.
Feliz [49]

Answer:

To the nearest hundredth, this is 30.79 units

Step-by-step explanation:

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to the nearest hundredth, this is;

30.79 units

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2 years ago
4w^3−8w+12<br> factor the polynomial<br><br> 5t^2+20t+50<br> factor the polynomial
DanielleElmas [232]
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3 years ago
What is the quotient of 2 divided by 1/6
jekas [21]
It is 12 since 1/6=6^-1=6
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5 0
3 years ago
Read 2 more answers
I need help with this problem I didn't really pay that much attention to this part of the subject.​
Flauer [41]

To check if a piecewise defined function is continuous, you need to check how the pieces "glue" together when you step from one domain to the other.

So, the question is: what happens at x=3? If you reach x=3 from values slightly smaller than 3, you obey the rule f(x)=log(3x). So, as you approach 3, you get values closer and closer to

\log(3\cdot 3)=\log(9)

Similarly, if you reach x=3 from values slightly greater than 3, you obey the rule f(x)=(4-x)log(9). So, as you approach 3, you get values closer and closer to

(4-3)\log(9)=\log(9)

So, the function is continuous at x=3, because both pieces approach log(9) as x approaches 3.

4 0
3 years ago
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