Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Answer:
The answer is H.
Step-by-step explanation:
There is no "b" in this y = mx + b, so it has to go through zero, eliminating the bottom two. If we insert y = 2(1), the point should be at (1, 2), and if when looking at the possible answers, we can go with letter H.
Answer:
69.993
Step-by-step explanation:
Using the percentage error formula:
Percentage error = (true - measured value / true measurement ) * 100%
1% error in measurement
1% of 69.3
0.01 * 69.3 = 0.693
True measurement = error in measurement + measured value
True measurement = 0.693 + 69.3
Actual measurement = 69.993
Hence, actual measurement = 69.993.