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3 years ago

1. The point A(-4,6) is rotated 90 degrees counterclockwise and then translated 3 units up.

Mathematics

1 answer:

professor190 [17]3 years ago

5 0

Answer:

Step-by-step explanation:

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A student completes about 8 problems every 3 minutes. At this rate, how long will it take the student to complete 20 problems?

storchak [24]

Answer:

Step-by-step explanation:

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3 years ago

How can you slice a rectangular prism to create a rectangular plane section with the largest possible

mafiozo [28]

Answer:

You can cut it horizantly, vertically and in the middle

Step-by-step explanation:

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3 years ago

Read 2 more answers

A car bought for $13,000 depreciates at 15% per year. Use an exponential function to find the value of the car after 5 years.

earnstyle [38]

Answer:

$5768.1

Step-by-step explanation:

Given data

Cost price= $13,000

Depreciation= 15%

Time= 5 years

The expression for the depreciation is given below

A= P(1-r)^t

Substitute

A=13000(1-0.15)^5

A=13000(0.85)^5

A=13000*0.4437

A=$5768.1

Hence after 5 years, the car will be $5768.1

7 0

3 years ago

Honda Atlas issued 100,000 shares of stock. In 1990, each share of stock was worth Rs. 152.50. In 1993, each share of the stock

noname [10]

Answer:

Rs.13,130 ,000

Step-by-step explanation:

Lets solve first for year 1990

Value of stock in 1990 = Rs. 152.50

No. of stocks issued in 1990 = 100,000

Total value of these stocks in 1990= Value of stock in 1990* no of stocks issued in 1990 = 152.50*100,000 = Rs. 15,250,000

Let solve first for year 1993

Value of stock in 1993 = Rs. 21.20

No. of stocks 1993 = 100,000

Total value of these stocks in 1993 = Value of stock in 1993* no of stocks issued in 1993 = 21.20*100,000 = Rs. 2,120,000

Decrease in value of stock in 1993 in comparison to 1990 = Total value of the stocks in 1990 -Total value of the stocks in 1993

= Rs. 15,250,000 - Rs. 2,120,000

= Rs.13,130 ,000

Thus, the 100,000 shares worth Rs.13,130 ,000 lesser in 1993 than in 1990.

6 0

3 years ago

Fernell and Dabney shared the driving

Agata [3.3K]

Answer:

15 hours

Step-by-step explanation:

Given:

Fernell's speed $v_F= 50$ mph

Dabney's speed $v_D= 64$ mph

Denote:

$D_F$ - distance covered by Fernell

$D_D$ - distance covered by Dabney

$t_F$ - Fernell's time

$t_D$ - Dabney's time

1. If Fernell drove for 3 hours longer than Dabney, then his time is 3 hours more than Dabney's time and

$t_F=t_D+3$

2. If Fernell covered 18 miles less than Dabney, then

$D_D-D_F=18$

Use formula $D=t\cdot v$

$D_D=v_D\cdot t_D\Rightarrow D_D=64\cdot t_D\\ \\D_F=v_F\cdot t_F\Rightarrow D_F=50\cdot (t_D+3)$

Subtract from the first equation the second equation and equate it to 18:

$64t_D-50(t_D+3)=18\\ \\64t_D-50t_D-150=18\\ \\14t_D=168\\ \\t_D=12\ \text{hours}$

$t_F=t_D+3=12+3=15\ \text{hours}$

5 0

3 years ago