Hey!
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Solution:
Put all the answer choices into expanded form.
3^9 = 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3
1^8 = 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1
9^3 = 9 x 9 x 9
8^1 = 8
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Answer:
We can see that the only way to write to write 9 x 9 x 9 in exponential form is c) 9^3
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Hope This Helped! Good Luck!
Firstly change the time into sec.that is
1 min=60 sec
5 min=60 into 5
=300 sec
speed=distance/time
=62.5/300
=0.20833333333333.............
Answer:
Initial equation: 5x + 2 = 3x + 12
x = 5
Step-by-step explanation:
Point C is the midpoint between A and B.
This means that:
AC = CB
We have that:
AC = 5x + 2
CB = 3x + 12
Since AC = CB, the initial equation is:
5x + 2 = 3x + 12
Now we can solve
5x + 2 = 3x + 12
5x - 3x = 12 - 2
2x = 10
x = 10/2
x = 5
<h3>
Answer: Choice C</h3>
The surface area of the pyramid is multiplied by 100.
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Explanation:
Consider a square that is 3 by 3. Its area is 3*3 = 9.
Then we'll multiply each dimension by 10 to get a 30 by 30 square. The new larger area is 30*30 = 900. The jump from the old area (9) to the new area (900) is "times 100". We can write 100 as 10^2, where the base of that exponential is the scale factor 10.
This idea can apply to any surface area and not just squares. This is why the surface area of the enlarged pyramid is 100 times that of the original pyramid.
new surface area = 100*(old surface area)
Answer:
see attachment
Step-by-step explanation:
The directions tell you what you need to know. It is a matter of adding up the values shown and finding the missing number to make the total be -20. Of course, it works best to start with a row, column, or diagonal that has 4 numbers already.Then, you're only finding the 5th number.
You can start with either diagonal, column 1 or 4, and row 4 or 5. Filling the missing numbers in those spots (red) will let you find the remaining missing numbers (green, then blue).
The square at row 2, column 2 can be filled on the first round using the down-right diagonal. I have shown it as filled on the second round after row 5 column 2 is filled.
Using a spreadsheet can make this easier, because you can write formulas for the sums in each row, column, and diagonal. Then you're just making those sums be -20.
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For example, consider the up-right diagonal. The sum of the given values, -6, 0, -4, -2, is -12. Then the spot at row 1, column 5 must be filled with -8 to make the sum be -20.
