Question

HELP ME I AM DUMB!!!!!!!!!!!!!!!!!!

Answer 1

Answer:

2H⁺(aq) + Sr(OH)₂(s) ⟶ Sr²⁺(aq) + 2H₂O(ℓ)

Explanation:

You aren't dumb. You just need more time to learn the concepts.

There are three steps you must follow. You must write the:

1. Molecular equation
2. Ionic equation
3. Net ionic equation

1. Molecular equation

2HBr + Sr(OH)₂ ⟶ SrBr₂ + 2H₂O

To predict the states of the substances, we must remember some solubility rules:

• HBr is a strong acid. It dissociates completely in water.
• Most hydroxides are only slightly soluble. Unless the solution is quite dilute, I would write their states in water as "(s)", i.e., a suspension of the solid in water.
• Salts containing Br⁻ are generally soluble.

Acids and bases react to give salts and water.

Thus, the molecular equation is

2HBr(aq) + Sr(OH)₂(s) ⟶ SrBr₂(aq) + 2H₂O(ℓ)

B. Ionic equation

You write all the soluble substances as ions.

2H⁺(aq)+ 2Br⁻(aq) + Sr(OH)₂(s) ⟶ Sr²⁺(aq) + 2Br⁻(aq) + 2H₂O(ℓ)

C. Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

2H⁺(aq) + 2Br⁻(aq) + Sr(OH)₂(s) ⟶ Sr²⁺(aq) + 2Br⁻(aq) + 2H₂O(ℓ)

The net ionic equation is

2H⁺(aq) + Sr(OH)₂(s) ⟶ Sr²⁺(aq) + 2H₂O(ℓ)