Answer:
The Ideal Gas Law cannot be applied to liquids. The Ideal Gas Law is #PV = nRT#. That implies that #V# is a variable. But we know that a liquid has a constant volume, so the Ideal <u><em>Gas Law cannot apply to a liquid.</em></u>
Explanation:
this is my awnser soory if it was a multiple choice question plz mark brainliest
Explanation: This is a reaction of oxidation of 
in the presence of acidified 
. Acidified is a strong oxidizing agent.
To balance out the 
on the reactant side, we write 
on the product side.
Balancing out the following reaction gives us:
Answer:
The new pressure is 0.5 atm
Explanation:
Step 1: Data given
Volume of oxygen = 300 mL = 0.300 L
Pressure = 1.00 atm
Temperature = 300 K
The volume increases to 1000mL = 1.00 L
The temperature increases to 500 K
Step 2: Calculate the new pressure
(P1*V1)/T1 = (P2*V2)/T2
⇒with P1 = the initial pressure = 1.00 atm
⇒with V1 = the initial volume = 0.300 L
⇒with T1 = the initial temperature = 300 K
⇒with P2 = the new pressure = TO BE DETERMINED
⇒with V2 = the increased volume = 1.00 L
⇒with T2 = the increased temperature = 500 K
(1.00 atm* 0.300 L)/300 K = (P2 * 1.00L) / 500 K
P2 = (1.00 *0.300 * 500) / (300 *1.00)
P2 = 0.5 atm
The new pressure is 0.5 atm
Answer: 2 moles
Explanation:
STP is Standard Temperature and Pressure. That means the pressure is 1.00 atm and the temperature is 273K. Since the oxygen is placed in the same container, we can use Ideal Gas Law to figure out what container the CO₂ used.
Ideal Gas Law: PV=nRT
P=1.00 atm
n=moles
R=0.08206 Latm/Kmol
T=273K
CO₂
Since we know that CO₂ has a 44.8 L container, we can use that to find the moles of oxygen.
There are 2 mol of oxygen.
, THR CC14 formed in the first step is used as the reactant used in the second step.if 5.00 mol of CH4 reacts, what is the total amount of HCI producded. assume that C12 an HR in the presentin excess
