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3 years ago

12

Explain why the level of greenhouse gasses in the atmosphere is rising.

1 answer:

Murljashka [212]3 years ago

3 0

Is a gas in the greenhouse that absorbs and emits radiation within the thermal infrared range.

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The acceleration of a sprinter is 10 m/s2. The force exerted on the starting blocks is 650 N. What is the mass of the sprinter?

jek_recluse [69]

The relation between force, mass of an object and its acceleration is given by following equation

F = mass of object X acceleration

The unit of Force is Newton (N)

unit of acceleration is ms⁻²

unit of mass if Kg

[all these are SI units]

Mass of object = $\frac{Force}{acceleration}$

mass of sprinter = $\frac{650}{10}=65kg$

5 0

3 years ago

Read 2 more answers

2. When paleontologists study fossils, which is true of the fossil record that they find?

juin [17]

Answer:

Explanation:

d

7 0

3 years ago

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The weight of a table as measured by a student is 20 kg.The

miskamm [114]

(20/23) times 100 is 87%

now the answer asks for percentage ERROR

100-87 =13

so answer is C

7 0

2 years ago

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How many formula units make up 36.0 g of magnesium chloride (MgCl2)?

zalisa [80]

Answer: There are $2.29\times 10^{23}$ formula units

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{36.0g}{95g/mol}=0.38moles$

1 mole of $MgCl_2$ contains = $6.023\times 10^{23}$ formula units

Thus 0.38 moles of $MgCl_2$ contains = $\frac{6.023\times 10^{23}}{1}\times 0.38=2.29\times 10^{23}$ formula units

Thus there are $2.29\times 10^{23}$ formula units

6 0

3 years ago

A solution is made by mixing of water and of acetic acid . Calculate the mole fraction of water in this solution. Be sure your a

Molodets [167]

Answer:

The answer is "0.35".

Explanation:

please find the complete question in the attached file.

Mass of $CH_3C0_2 H$ $= 77 \ g \\\\$

Molar mass of $CH_3C0_2 H$ $= 60.05 \ \frac{g}{mol} \\\\$

No of moles in $n_{CH_3CO_2H}$ $= 77 \ g \times \frac{1 \ mol \ CH_3C0_2H}{60.05 \ g}$

$= 1.28 \ mol \ CH_3CO_2H$

Mass of water $(H_2O)$ $= 42 \ g$

The molar mass of water $(H_2O)$ $= 18.02 \ \frac{g}{mol}$

moles of water $n_{H_2O}$ :

$= 42 \ g \times \frac{1 mol H_2O}{18.02 \ g} \\\\= 2.33 \ mol \ H_2 O$

Molfraction of acetic acid:

$X CH_2CO_2H = \frac{n_{CH_3CO_2H}}{n_CH_3CO_2H +n_{H_2}}\\\\$

$=\frac{1.28 \ mol}{1.28 \ mo1 + 2.33 mol}\\\\ = 0.354\\\\= 0.35$

7 0

3 years ago