Then, at a critical point during interphase (called the S phase), the cell duplicates its chromosomes and ensures its systems are ready for cell division. If all conditions are ideal, the cell is now ready to move into the first phase of mitosis.
Answer:
The heat needed to boil 1 gallon of water is 81,490.62 Joules.
Explanation:

Where:
Q = heat absorbed or heat lost
c = specific heat of substance
m = Mass of the substance
ΔT = change in temperature of the substance
We have :
Volume of water = V = 1 gal = 4546.09 mL
Density of water , d= 1 g/mL
mass of water = m = d × V = 1g/mL × 4546.09 mL = 4546.09 g
Specific heat of water = c = 1 Cal/g°C
ΔT = 100°C - 25°C = 75 °C
9 (boiling pint of water is 100°C)
Heat absorbed by the water to make it boil:

1 calorie = 4.184 J

The heat needed to boil 1 gallon of water is 81,490.62 Joules.
Explanation:
The highest number is the strongest base. Therefore the pH of 12 is the strongest base here (C).
Electrolysis is a process, which allows us to break down a chemical compound into its elements, completing the balance by adjusting the number of atoms on both sides of the reaction is important because the number of electrons given up during oxidation must be the same as the number of electrons gained during the reduction.
<h3>What is electrolysis of water?</h3>
It is a process of oxidation and reduction of one or more elements that, through the induction of electric current, breaks down the water molecule (H2O), thus producing gaseous hydrogen and oxygen.
Oxidation and reduction processes occur simultaneously and never in isolation, which is why they are called redox reactions.
Therefore, we can conclude that electrolysis is a process where electrical energy will change to chemical energy where it is important that the number of electrons given up during oxidation is the same as the number of electrons gained during reduction.
Learn more about balance of redox equations : brainly.com/question/1232351
Answer:
=60 milligrams
Explanation:
12 x 5
=60 milligrams
Have a nice day!!!!!!! :-)
<u>KA</u>