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gulaghasi [49]
4 years ago
8

According to kinetic-molecular theory, which of the following would not be considered an ideal gas? Check all that apply.

Chemistry
2 answers:
Whitepunk [10]4 years ago
5 0

Answer:

a gas at very low volumes, when gas particles are very close together

a gas at very low temperatures, when gas particles have very little kinetic energy

a gas with highly polar molecules that have very strong intermolecular forces

Explanation:

Vikki [24]4 years ago
4 0

Answer:

are a gas at very low volumes, when gas particles are very close together

a gas at very low temperatures, when gas particles have very little kinetic energy

a gas with highly polar molecules that have very strong intermolecular forces

Explanation:

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3. Determine the moles of sodium, Na, containing 7.9x1024 atoms.​
-BARSIC- [3]

Answer:

12.7mol Na.

Explanation:

Hello there!

In this case, according to the concept of mole, which stands for the amount of substance, we can recall the concept of Avogadro's number whereby we understand that one mole of any substance contains 6.022x10²³ particles, for the given atoms of sodium, we can calculate the moles as shown below:

7.9x10^{23}atoms*\frac{1mol}{6.022x10^{23}atoms} \\\\

Thus, by performing the division we obtain:

12.7molNa

Regards!

8 0
3 years ago
78.5 mol of P4O10 contains how many moles of P?
MArishka [77]
<span>4 x 36 moles. of Phosporus and 10 x 36 of Oxygen. I hope this helps. (:</span>
7 0
3 years ago
A particular uranium alloy has a density of 18.75 g/cm3.
soldi70 [24.7K]

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5 0
3 years ago
How many molecules (not moles of nh3 are produced from 5.01×10?4 g of h2?
Irina-Kira [14]
2,02g     -------    6,02×10²³
5,01×10⁴g  ---    x

x=\frac{5,01*10^{4}g*6,02*10^{23}}{2,02g}=14,93*10^{27}

N₂         +        3H₂       ⇒           2NH₃
1mol      :        3mol        :           2mol
                       18,06×10²³  :       12,04×10²³
                       14,93×10²⁷  :        y

y=\frac{14,93*10^{27}*12,04*10^{23}}{18,06*10^{23}}\approx9,95*10^{27}
5 0
3 years ago
The compound adrenaline contains 56.79% c, 6.56% h, 28.37% o, and 8.28% n by mass. what is the empirical formula for adrenaline?
Phoenix [80]
To determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that we assume to have 100 grams sample of the compound with the given composition. Then, we calculate for the number of moles of each element. We do as follows:<span>
         mass        moles
C       56.79        4.73
H       6.56          6.50
O       28.37        1.77
N      8.28           0.59

Dividing the number of moles of each element with the smallest value, we will have the empirical formula:

</span>         moles                 ratio
C       4.73     / 0.59       8
H       6.50     / 0.59      11
O       1.77     / 0.59       3
N        0.59    / 0.59       1<span>
</span><span>
The empirical formula would be C8H11O3N.</span>
8 0
3 years ago
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