Answer: C
Step-by-step explanation:
1) Multiply (2x+8)(6x+2)
2) After you do the math you will get 12x^2+52x+16
REMEMBER: A= Length times width
Answer:
Vertical angle=9.5°
Time to reach maximum height = 1.24seconds
Step-by-step explanation:
The maximum distance x is reached when rope swings to a maximum height, maximum height is gotten from the equation KE= 1/2MU^2 = MgH = MgL= Mgl(1- cos theta.
Where theta is the vertical angle, U=2m/s and L= 15m
2gl -2glcostheta=U^2
2gl U^2=2gl cos theta
But theta= Acos(1- U^2)/2gl
Acos(1-/(2×9.8×15)
Theta =9.5°
Maximum height li given by
Lsintheta
But X= UxT
T=X/UX= Lsintheta/U = 15sin9.5 /2 =1.24seconds
Length x width x height
4 x 5 = 20
20 x 6 = 120 cm^3
So hi
In order to do this problem you do, 5/9×10
The answer will be 50/9 which is 5 5/9.
~JZ
Hope it helps
