After 8 classes
40 divided by 5 is 8 so after 8 classes
Answer:
what box please ¯\_ಠ_ಠ_/¯
Answer:
The three zeros of the original function f(x) are {-1/2, -3, -5}.
Step-by-step explanation:
"Synthetic division" is the perfect tool for approaching this problem. Long div. would also "work."
Use -5 as the first divisor in synthetic division:
------------------------
-5 2 17 38 15
-10 -35 -15
--------------------------
2 7 3 0
Note that there's no remainder here. That tells us that -5 is indeed a zero of the given function. We can apply synthetic div. again to the remaining three coefficients, as follows:
-------------
-3 2 7 3
-6 -3
-----------------
2 1 0
Note that the '3' in 2 7 3 tells me that -3, 3, -1 or 1 may be an additional zero. As luck would have it, using -3 as a divisor (see above) results in no remainder, confirming that -3 is the second zero of the original function.
That leaves the coefficients 2 1. This corresponds to 2x + 1 = 0, which is easily solved for x:
If 2x + 1 = 0, then 2x = -1, and x = -1/2.
Thus, the three zeros of the original function f(x) are {-1/2, -3, -5}.
Answer:
0
Step-by-step explanation:
Isolate the variable x. First, distribute 3 to all terms within the parenthesis.
3(2x + 3) = 3(2x) + 3(3) = 6x + 9
6x + 9 = 9
Isolate the variable x. Note the equal sign, what you do to one side, you do to the other. First, subtract 9 from both sides.
6x + 9 (-9) = 9 (-9)
6x = 0
Divide 6 from both sides.
(6x)/6 = (0)/6
x = 0
0 is your answer.
~
Your answer is Y= 0x-2b .
This is because it hits -2 on the y axis.
