Answer:
Since EF bisects ∠DEF, we know that EF splits ∠DEF in 2 halves from the word 'bisects', which can be written as 'bi- sects' , where bi means 2 and sects means sections
Hence, ∠DEG = ∠GEF --------------(1)
We are given the measure of these angles:
∠DEG = 3x - 4
∠GEF = x + 13
Now, replacing the values in (1):
3x - 4 = x + 13
2x = 17
x = 17/2
Now, finding the measure of ∠DEF:
∠DEF = ∠DEG + ∠GEF
∠DEF = 3x - 4 + x + 13
∠DEF = (51 / 2) - 4 + (17/2) + 13 (x = 17/2)
∠DEF = 34 - 4 + 13
∠DEF = 43°
The answer is C.
Proof:
8×4-(2×3+8)÷2
=32-(6+8)÷2
=32-14÷2
=32-7
=25
Answer: (below)
Step-by-step explanation:
1) n/6 + 6 = -3
2) 2n + 5 = 27
3) n/2 - 10 = 5
Answer:
20,053
Step-by-step explanation:
20,335 - 282 = 20,053
Answer: The pupil's area is π mm^2 or 3.14mm^2
Step-by-step explanation:
First of all, the pupil is the name that is given to the hole that is situated in the centre of the Iris of the human eye which allows light to come in contact with the retina. It adjusts in size (diameter) depending on the availability of light in the environment we find ourselves.
In this scenario, Shannon entered the room with unusual lighting and her pupil's diameter adjusted to 2 millimeters.
Now, it is important to note that a pupil is an example of a circle.
The formula for finding or calculating the area of a circle is πr^2, where π = 22/7 and "r" = radius.
Since the radius of her pupil is = 2/2 = 1 millimetre, the area of the pupil is:
πr^2 = π × 1 × 1 = π mm^2
Or 22/7 × 1 × 1
= 3.14mm^2
Therefore the area of her pupil when she entered the room with unusual lighting is 3.14mm^2
