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3 years ago

4t2–40t+84 factorise quadratics

Mathematics

2 answers:

Evgen [1.6K]3 years ago

6 0

Answer:

4( t - 7) ( t - 3 )

Step-by-step explanation:

4t² - 40t + 84

4(t² - 10t + 21)

4( t - 7) ( t - 3 )

Viktor [21]3 years ago

5 0

Answer:

4(t − 3)(t − 7)

Step-by-step explanation:

4(t–3)(t–7)

4(t2–3t–7t+21)

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What is area of this shape

german

Answer:

132 ft squared

Step-by-step explanation:

One way is to divide the shape into a rectangle and a triangle, by drawing a vertical line.

This gives a rectangle that is 9 by 11, so has area 99.

The triangle has a base of 11 and height of 15 - 9 = 6.

So the area of the triangle = 1/2 x b x h = 1/2 x 11 x 6 = 33

So the total area is 99 + 33 = 132.

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3 years ago

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3 years ago

How many 5mL doses are in a 5fl oz bottle of antibiotic preparation

Andrews [41]

Hello. I'm Dr. Phil, licensed and practicing Internal Medicine Physician. Excellent service is my goal.

Thanks for this question

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I hope this helps.

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3 years ago

Just need to know what x is haha

marishachu [46]

Answer: x=14

Step-by-step explanation:

The angles in a triangle are equal to 180 so

6x + 3 + 5x + x + 9 = 180

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4 0

4 years ago

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago