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Darya [45]
3 years ago
14

Answer and show the work please?

Mathematics
1 answer:
Marat540 [252]3 years ago
7 0
You correct its 8.8 peace
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Pythagorean triples are given by the formulas x2 - y2, 2xy, and x2 + y2. Use the formulas for the Pythagorean triples to prove w
Arte-miy333 [17]
Let k be an integer. Suppose there is a triangle with legs of length 16 and 2k+1. Then by the Pythagorean theorem, the length of the hypotenuse should be

\sqrt{16^2+(2k+1)^2}=\sqrt{4k^2+4k+257}

The formulas for Pythagorean triples say that if the legs are integers, then so must be the hypotenuse, because if x=16 and y=2k+1 are integers, then so are x^2-y^2, 2xy, and x^2+y^2.

However, 4k^2+4k+257 is not a perfect square trinomial, which means for any integer k, the length of the hypotenuse is not an integer, so such a triangle doesn't exist.
4 0
2 years ago
Linda's dog ate 6 cans of dog food this week. Each can contained 44.7 grams of protein. How much protein was this in all?
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Answer:

268.2 grams

Step-by-step explanation:

44.7 times 6

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4 0
3 years ago
NEED HELP!!! graph <br> y&lt;1−3x
vekshin1

A graph and a table are provided below this discussion. You should plot these in this order.

y = 1 - 3x    In red. It might be hard to see

y < 1 - 3x    In blue

The table which is to the left of the graph

The table is constructed by putting a value in for x

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y = 1 - 6

y = - 5



8 0
3 years ago
Question 3 of 10
yarga [219]

Answer: 60000

Step-by-step explanation:

The ten thousands place is the 5th digit from the right. Because the digit in the thousands place is less than 5, round down to 60000.

3 0
2 years ago
Read 2 more answers
Corresponding points must be an equal distance from the Line of Reflection.
d1i1m1o1n [39]
It is true that corresponding points must be an equal distance from the Line of reflection. This is because in cases of reflection, the image is far behind the mirror or line of reflection as the object is in front of the mirror. What this proposition means is, the distance from the object to the line of reflection is equal to the distance between the reflection line and the image. There sizes are bound to be equal to, and hence the two corresponding points will be similar. 
7 0
3 years ago
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