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r-ruslan [8.4K]
3 years ago
10

The questions below walk through the use of kNN to predict the value of Y for a new point with (X1, X2)=(4, 4). Distance is calc

ulated in the Euclidean sense.
What is the Euclidean distance between (X1,X2)=(4,4) and the first point in the table ((X1,X2)=(3,5))?
Mathematics
1 answer:
Nady [450]3 years ago
5 0

Answer:

The Euclidean distance between the two given points is \sqrt{2}\text{ units}.

Step-by-step explanation:

K-NN is used to predict the variable y for a new point with (X_1,X_2) = (4,4)

Distance is calculated in the Euclidean sense.

The Euclidean distance between two points is given by the formula:

\text{Points: }(X_1, X_2), (x_1,x_2)\\\\D = \sqrt{{(x_2-X_2)}^2 + (x_1-X_1)^2}

The point is (x_1,x_2) = (3,5)

The Euclidean distance between the two points is given by:

D = \sqrt{(5-4)^2 + (3-4)^2} = \sqrt{2}\text{ units}

Thus, the Euclidean distance between the two given points is \sqrt{2}\text{ units}.

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