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3 years ago

Solve. 3/9A = 81 a = 9 a=81 3/9 a = 27 a = 243

Mathematics

1 answer:

Harrizon [31]3 years ago

6 0

To solve for A, multiply each side by 9A to get rid of the fraction, so then 3 = 81(9A) --> 3 = 729A --> 3/729 = 1/243

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If anyone can give me the answer that will be greatly appreciated :)

vfiekz [6]

42-x=58

or, -x=58-42

with change in side sign also chamges we change sides to make like terms in one side and unlike in amother side.

or, -x= 16

or,x=-16.

therefore x=-16...

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>

3 0

2 years ago

Cylinders A and B are similar solids. The base of cylinder A has a circumference of 47 units. The base of cylinder B has an

fiasKO [112]

<h3><u>Question:</u></h3>

Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4π units. The base of cylinder B has an area of 9π units.

The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?

<h3><u>Answer:</u></h3>

Dimensions of cylinder A are multiplied by $\frac{3}{2}$ to produce the corresponding dimensions of cylinder B

<h3><u>Solution:</u></h3>

Cylinders A and B are similar solids.

The base of cylinder A has a circumference of $4 \pi$ units

The base of cylinder B has an area of $9 \pi$ units

Let "x" be the required factor

From given question,

Dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B

Therefore, we can say,

$\text{Dimensions of cylinder A} \times x = \text{Dimensions of cylinder B }$

<h3><u>Cylinder A:</u></h3>

The circumference of base of cylinder (circle ) is given as:

$C = 2 \pi r$

Where "r" is the radius of circle

Given that base of cylinder A has a circumference of $4 \pi$ units

Therefore,

$4 \pi = 2 \pi r\\\\r = 2$

Thus the dimension of cylinder A is radius = 2 units

<h3><u>Cylinder B:</u></h3>

The area of base of cylinder (circle) is given as:

$A = \pi r^2$

Given that, the base of cylinder B has an area of $9 \pi$ units

Therefore,

$\pi r^2 = 9 \pi\\\\r^2 = 9\\\\r = 3$

Thus the dimension of cylinder B is radius = 3 units

$\text{Dimensions of cylinder A} \times x = \text{Dimensions of cylinder B }\\\\2 \times x = 3\\\\x = \frac{3}{2}$

Thus dimensions of cylinder A are multiplied by $\frac{3}{2}$ to produce the corresponding dimensions of cylinder B

5 0

3 years ago

1. (SLO) Simplify the expression: 6(b-7)

Sav [38]

1 → B

multiply each term in the parenthesis by the 6 outside

6(b-7) = 6b - 42

2 → D

multiply each term in the parenthesis by the 3 outside

3(4x+6y+2) = 12x+18y+6

3 → A

the value outside the parenthesis is -1, hence each term inside is multiplied by -1

-1(6x+5y) = -6x -5y

3 0

3 years ago

Read 2 more answers

Brian needs to buy some pencils bread I had a pack of 12 pencils for 298 when we has a pack of a pack of 18 pencils for 499 find

AlekseyPX

Answer:

The pack of 12 pencils for 298 is better as it has a lower unit price.

Step-by-step explanation:

To be able to find the answer, you have to calculate the unit price for each brand by dividing the price of the pack by the number of pencils in the pack.

-298/12=24.83

-499/18=27.72

According to this, the answer is that the pack of 12 pencils for 298 is better as it has a lower unit price.

8 0

3 years ago

AngleRQT is a straight angle. What are m angleRQS and m angleTQS?<br><br> m angleRQS=

lara31 [8.8K]

$\widehat{RQS}+\widehat{TQS}=\widehat{RQT}\\\Leftrightarrow 9x + 1 + 7x + 3 = 180 \\ \widehat{RQS}+\widehat{TQS}=\widehat{RQT}\\\Leftrightarrow 16x = 176\Leftrightarrow x = 11 \\ \Rightarrow \widehat{RQS} = 9 \times 11 + 1 = 100° \: \wedge \: \widehat{TQS} = 7 \times 11 + 3 = 80°$

4 0

3 years ago