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elena-s [515]
3 years ago
9

The diagonal of a square measured 10 cm. Find the length of a side of the square to the nearest tenth.

Mathematics
1 answer:
Naddika [18.5K]3 years ago
6 0

Answer:

  7.1 cm

Step-by-step explanation:

Let s represent the side length of the square. The Pythagorean theorem tells you the relationship to the diagonal length is ...

  (10 cm)² = s² +s² . . . . the sum of the squares of the legs is the square of the hypotenuse

  100 cm² = 2s² . . . . . . simplify

  50 cm² = s² . . . . . . . . divide by 2

  √(50) cm = s ≈ 7.1 cm . . . . . take the square root

The length of a side of the square to the nearest tenth is 7.1 cm.

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You are working for a company that designs boxes, bottles and other containers. You are currently working on a design for a milk
ra1l [238]

Volume is a measure of the <u>quantity </u>of <em>substance</em> a given <u>object</u> can contain. The required answers are:

1.1  The <u>volume</u> of each <u>milk</u> carton is 360 cm^{3}.

1.2  The area of <em>cardboard</em> required to make a single <u>milk</u> carton is  332.6 cm^{2}.

1.3  Each <u>carton</u> can hold 0.36 liters of <u>milk</u>.

1.4  The <em>cost</em> of filling the 200 <u>cartons</u> is R 86.40.

The <u>volume</u> of a given <u>shape</u> is the amount of <em>substance</em> that it can contain in a 3-dimensional <em>plane</em>. Examples of <u>shapes</u> with volume include cubes, cuboids, spheres, etc.

The <u>area</u> of a given <u>shape</u> is the amount of <em>space</em> that it would cover on a 2-dimensional <em>plane</em>. Examples of <u>shapes</u> to be considered when dealing with the area include triangle, square, rectangle, trapezium, etc.

The box to be considered in the question is a <u>cuboid</u>. So that;

<u>Volume</u> of <u>cuboid</u> = length x width x height

Thus,

1.1 The <u>volume</u> of each <u>milk</u> carton = length x width x height

                                                         = 6 x 6 x 10

                                                        = 360

The <u>volume</u> of each <u>milk</u> carton is 360 cm^{3}.

1.2 The <em>total area</em> of<em> cardboard </em>required to make a single<u> milk</u> carton can be determined as follows:

i. <u>Area</u> of the <u>rectangular</u> surface = length x width

                                                    = 6 x 10

                                                    = 60

Total <u>area</u> of the <u>rectangular</u> surfaces = 4 x 60

                                                     = 240 cm^{2}

ii. <u>Area</u> of the <u>square</u> surface = side x side = s²

                                                   = 6 x 6  

 <u>Area</u> of the <u>square</u> surface = 36 cm^{2}

iii. There are four <em>semicircular</em> <u>surfaces</u>, this implies a total of 2 <u>circles</u>.

<em>Area</em> of a <u>circle</u> = \pi r^{2}

where r is the <u>radius</u> of the <u>circle</u>.

Total <u>area</u> of the <em>semicircular</em> surfaces = 2 \pi r^{2}

                                        = 2 x \frac{22}{7} x (3)^{2}

                                        = 56.57

Total <u>area</u> of the <em>semicircular</em> surfaces = 56.6 cm^{2}

Therefore, total area of  <em>cardboard</em> required = 240 + 36 + 56.6

                                                            = 332.6 cm^{2}

The <u>area</u> of <em>cardboard</em> required to make a single <em>milk carton</em> is  332.6 cm^{2}.

1.3 Since,

  1 cm^{3}  = 0.001 Liter

Then,

360 cm^{3} = x

x = 360 x  0.001

  = 0.36 Liters

Thus each<em> carton</em> can hold 0.36 liters of <u>milk</u>.

1.4 total cartons = 200

<em>Total volume</em> of <u>milk </u>required = 200 x 0.36

                                                 = 72 litres

But, 1 kiloliter costs R1 200. Thus

<em>Total volume</em> in kiloliters = \frac{72}{1000}

                                         = 0.072 kiloliters

The <u>cost</u> of filling the 200 cartons = R1200 x 0.072

                                         = R 86.40

The <u>cost</u> of filling the 200 <u>cartons</u> is R 86.40.

For more clarifications on the volume of a cuboid, visit: brainly.com/question/20463446

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4 0
2 years ago
What is the series in Expanded Form?
tangare [24]

Answer:

∴ ∑₁⁸i = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8

Step-by-step explanation:

Given:

To Find:

∑₁⁸i =?

Solution:

Σ   This symbol called Sigma means "summation up"

∴ ∑ n mean sum for all n

But if ∑₁³n means  Sum for n=1 , 2 ,and 3 ADD

∴ ∑₁³n = 1 + 2 + 3

∴ ∑₁⁸i = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8

7 0
3 years ago
Solve x and y <br><br>x/2 + y/3 = 4<br>7x - y = 12​
Anestetic [448]

Answer: here the answer

Step-by-step explanation:

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3 years ago
Which unit would use used to measure the capacity? Milliliter or liters For a bucket
frozen [14]

Answer:

Liters

Step-by-step explanation:

Milliliters are used to measure smaller amount of liquids while liters are used for bigger. If you were to use a bucket, you would need to measure the capacity with bigger measurements.

7 0
2 years ago
First person to help gets brainliest
lions [1.4K]

The solution of the given equation w.r.t m is m = 3 ,i.e., option A

<h3>What are Algebraic equations?</h3>

With one exception, algebraic equations are essentially algebraic expressions.

An = sign is required in all algebraic equations.

No matter what kind of equation it is, all equations use the = sign.

The next topic is algebraic expression, which lacks the operators =,,, >, and.

To put it simply, there is no comparison between two terms in an algebraic statement.

Algebraic expressions frequently use terms like polynomial and square root.

So you now recognize the distinction between the two?

1) An algebraic equation has the symbol =, and 2) an algebraic expression lacks any comparison symbols (such as > and =).

As per the question:

6\frac{1}{9} + 3\frac{1}{3} =28\frac{1}{3}

55/9 + 10/3 = 85/3

(55m+30m)/9 = 85/3

85m/9 = 85/3

85m = (85*9)/3

85m = 85*3

m = (85*3)/85

∴ m = 3

To now more about algebraic equations, visit

brainly.com/question/953809

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5 0
1 year ago
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