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2 years ago

The diagonal of a square measured 10 cm. Find the length of a side of the square to the nearest tenth.

Mathematics

1 answer:

Naddika [18.5K]2 years ago

6 0

Answer:

7.1 cm

Step-by-step explanation:

Let s represent the side length of the square. The Pythagorean theorem tells you the relationship to the diagonal length is ...

(10 cm)² = s² +s² . . . . the sum of the squares of the legs is the square of the hypotenuse

100 cm² = 2s² . . . . . . simplify

50 cm² = s² . . . . . . . . divide by 2

√(50) cm = s ≈ 7.1 cm . . . . . take the square root

The length of a side of the square to the nearest tenth is 7.1 cm.

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NARA [144]

Answer:

PB = 1.8

Step-by-step explanation:

PQ = 8 cm, BC = 10 cm and AB = 9 cm

∆ABC is similar to ∆APQ.

Therefore:

$\frac{AB}{AP} = \frac{BC}{PQ}$

Plug in the values

$\frac{9}{AP} = \frac{10}{8}$

Cross multiply

AP × 10 = 8 × 9

AP × 10 = 72

Divide both sides by 10

AP = 7.2

PB = AB - AP

PB = 9 - 7.2

PB = 1.8

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{a+c=529
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{9a+9c=4761
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