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3 years ago

the beer at the electronic store was $81 before taxes the taxes is 7% what is the total of the price with tax

Mathematics

1 answer:

irga5000 [103]3 years ago

7 0

Beer? at an electronic store? but srsly, 81*.07 is 5.67, total is 86.67

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Blake and three friends meet for lunch. His friends all get the same thing, but Blake gets a different lunch that cost $6. Write

sladkih [1.3K]

Answer:

Step-by-step explanation:

Friends lunch=8+8+8=$32

Blake's lunch=$6

32+6=$40 total

6 0

3 years ago

Angel invests money in an account paying simple interest. He invests $110 and no money is added or removed from the investment.

Elena-2011 [213]

Answer:

82.8

Step-by-step explanation:

4 0

2 years ago

Help please, also explain

olga55 [171]

Firstly, It says that the two triangles are similar .

The scale factor is 2 as 12 / 6 = 2

25 + 85 = 110

180 - 110 = 70.

70 degrees

8 0

3 years ago

Read 2 more answers

12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle TPQ, 

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, RS || PQ

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

Now, We know 

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

3 0

2 years ago

The capacity of an elevator is 12 people or 2088 pounds. the capacity will be exceeded if 12 people have weights with a mean gre

boyakko [2]

suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.

Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?

Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.

Mean = 177

standard deviation = 26

We find z-score using given mean and standard deviation

z = $\frac{x-mean}{standard deviation}$

= $\frac{174-177}{26}$

=-0.11538

Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)

= 0.5438

P(weight will be greater than 174 lb) = 0.5438

8 0

3 years ago