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sesenic [268]
3 years ago
12

What is 1 over 2 mean?

Mathematics
2 answers:
ddd [48]3 years ago
8 0

Answer: 1 over 2 means fraction formant.

Step-by-step explanation: So if you where to say you ate 1 over 2 slice of cake then, you have 1/2.

Debora [2.8K]3 years ago
3 0

Answer:

One out of two, or half.

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Calculate a four-day moving average for the price of the stock for the end of day 7. day 1 - 62.00; day 2 - 56.00; day 3 - 50.00
Aneli [31]

At day 7, the four-day moving average for the price of the stock would be $58.25.

<h3>What is the four-day moving average at day 7?</h3>

This can be found as:

= (Day 7 price + Day 6 + Day 5 + Day 4) / Number of days

Solving gives:

= (59 + 55 + 59 + 60) / 4

= 233 / 4

= $58.25

Find out more on moving averages at brainly.com/question/15188858.

#SPJ1

8 0
2 years ago
The composite figure is made up of a rectangular prism and a___a0___.a1
zavuch27 [327]

Answer:

The composite figure is made up of a rectangular prism and  square pyramid

Step-by-step explanation:

The figure on top is square pyramid since the base is a square and the 4 sides are triangles.  The bottom is a rectangular prism since the figure is made up of side rectangular faces

8 0
3 years ago
Problem 4: Let F = (2z + 2)k be the flow field. Answer the following to verify the divergence theorem: a) Use definition to find
Viktor [21]

Given that you mention the divergence theorem, and that part (b) is asking you to find the downward flux through the disk x^2+y^2\le3, I think it's same to assume that the hemisphere referred to in part (a) is the upper half of the sphere x^2+y^2+z^2=3.

a. Let C denote the hemispherical <u>c</u>ap z=\sqrt{3-x^2-y^2}, parameterized by

\vec r(u,v)=\sqrt3\cos u\sin v\,\vec\imath+\sqrt3\sin u\sin v\,\vec\jmath+\sqrt3\cos v\,\vec k

with 0\le u\le2\pi and 0\le v\le\frac\pi2. Take the normal vector to C to be

\vec r_v\times\vec r_u=3\cos u\sin^2v\,\vec\imath+3\sin u\sin^2v\,\vec\jmath+3\sin v\cos v\,\vec k

Then the upward flux of \vec F=(2z+2)\,\vec k through C is

\displaystyle\iint_C\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^{\pi/2}((2\sqrt3\cos v+2)\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm dv\,\mathrm du

\displaystyle=3\int_0^{2\pi}\int_0^{\pi/2}\sin2v(\sqrt3\cos v+1)\,\mathrm dv\,\mathrm du

=\boxed{2(3+2\sqrt3)\pi}

b. Let D be the disk that closes off the hemisphere C, parameterized by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath

with 0\le u\le\sqrt3 and 0\le v\le2\pi. Take the normal to D to be

\vec s_v\times\vec s_u=-u\,\vec k

Then the downward flux of \vec F through D is

\displaystyle\int_0^{2\pi}\int_0^{\sqrt3}(2\,\vec k)\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv=-2\int_0^{2\pi}\int_0^{\sqrt3}u\,\mathrm du\,\mathrm dv

=\boxed{-6\pi}

c. The net flux is then \boxed{4\sqrt3\pi}.

d. By the divergence theorem, the flux of \vec F across the closed hemisphere H with boundary C\cup D is equal to the integral of \mathrm{div}\vec F over its interior:

\displaystyle\iint_{C\cup D}\vec F\cdot\mathrm d\vec S=\iiint_H\mathrm{div}\vec F\,\mathrm dV

We have

\mathrm{div}\vec F=\dfrac{\partial(2z+2)}{\partial z}=2

so the volume integral is

2\displaystyle\iiint_H\mathrm dV

which is 2 times the volume of the hemisphere H, so that the net flux is \boxed{4\sqrt3\pi}. Just to confirm, we could compute the integral in spherical coordinates:

\displaystyle2\int_0^{\pi/2}\int_0^{2\pi}\int_0^{\sqrt3}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=4\sqrt3\pi

4 0
3 years ago
17:3 and 15:60 Equivalent ratios
inessss [21]

Answer:

Step-by-step explanation:

17:3 is already in lowest terms. 17:3 = 34:6, 51:9, etc.

15:60 = 1:4

5 0
2 years ago
2854 / 32<br><br> A. 89<br> B. 89 3/16<br> C. 89 5/16<br> D. 89 3/8
Marrrta [24]
Its b
2854/32 = 1427/16 = 89 3/16
7 0
3 years ago
Read 2 more answers
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