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3 years ago

What is 5.8×106 seconds in minutes?

Mathematics

2 answers:

den301095 [7]3 years ago

7 0

Answer:

3.48x108=375.84

Step-by-step explanation:

5.8x106=614.8

9.67x108=1044.36

9.67x104=1005.68

3.48x108=375.84

3.48x104=361.92

Alinara [238K]3 years ago

3 0

The answer is 375.84

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Michael multiplies 0.4 by a number. He records the product as 0.012. What number did Michael use? Michael used

Free_Kalibri [48]

Answer:

0.03

Step-by-step explanation:

Calculation for What number did Michael used

Using this formula

Number used=Number of Product recorded/Number multiplied

Let plug in the formula

Number used =0.012/0.4

Number used =0.03

CHECK: 0.4*0.03=0.012

Therefore the number that Michael used is 0.03

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3 years ago

Pls give an explanation u don't have to... I'll give brainly if right!

Maru [420]

Answer:

72.9

Step-by-step explanation:

Multiply your first 2 terms

4.5* (-9) = -40.5

multiply this by -1.8

-40.5*-1.8 = 72.9

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3 years ago

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Elodia [21]

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3 years ago

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Geometry help plz will mark brainliest.

Alex17521 [72]

I think it's 12x.
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3 years ago

2. Solve the system of equations. Write your answer in parametric vector notation. X, +5x2 + 4x3 + 3x4 +9xs = 18 2x, +6x2 + 4x3

ratelena [41]

Answer:

The system is inconsistent.

Step-by-step explanation:

The system is

$x_1+5x_2+4x_3+3x_4+9x_5=18\\2x_1+6x_2+4x_3+6x_4+6x_5=28\\3x_1+7x_2+4x_3+10x_4+x_5=41\\4x_1+6x_2+2x_3+7x_4+4x_5=29$

The associated matrix to the system is

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\2&6&4&6&6&28\\3&7&4&10&1&41\\4&6&2&7&4&29\end{array}\right]$

Now we use row operations to find the echelon form of the matrix:

1. We substract to row 2, two times the row 1.

We substract to row 3, three times the row 1.

We substract to row 4, four times the row 1 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&-4&-4&0&-12&-8\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]$

2. We multiply the second row of the preview step by -1/4. We obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]$

We add to row 3, eight times the row 2.

We add to row 4, fourtheen times the row 2 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&-5&10&-155\end{array}\right]$

4. We add to row 4 of the preview step, five times the row 3 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&0&0&-140\end{array}\right]$

Using backward substitution we have that

$0x_5=-140$ , then $0=-140$ and this is absurd. Then The system is inconsistent.

4 0

4 years ago