A bearing of 34° corresponds to corresponding angle of θ=90-34=56°
The (x,y) values for the position of the ship after completing its first heading are:
x=(10.4cos 56)
y=(10.4sin56)
The trigonometric angle for θ=90-90=0
The (x,y) values for the postion of the ship after completing the second bearing is:
x=(10.4 cos56)+(4.6cos0)≈10.4 mi
y=(10.4sin56)+(4.6sin0)≈8.6mi
the distance from the port will therefore be:
d=√(10.4²+8.6²)≈13.5 miles
It trigonometric angles is:
θ=arctan(y/x)
θ=arctan(8.6/10.4)
θ≈39.6°
Thus the bearing angle is:
90-39.6=50.4°
Answer: C. 5(6) + 0.65y
Step-by-step explanation:
Process of elimination.
65% of y = 0.65y
A has 65y, completely incorrect.
B has 6y, also completely incorrect.
<u>C has 0.65y, correct.</u>
D has 1.65y, also completely incorrect.
Answer:
The answer is A.
Step-by-step explanation:
The answer is A because an obtuse angle rounds to 120 degrees, then you divide it by 6 which is A.
Answer: She is incorrect because 0 + 0 = <u>0</u>
Answer:
432m^3
Step-by-step explanation:
The computation of the volume of the larger pyramid is shown below:
Let us assume the volume of the larger pyramid be x
Given that
The ratio of two pyramids is 25:36
We can say that
The Ratio of side = (The ratio of surface area)^
= 
Now
ratio of volume = (ratio of side)^3 = 
= 125 : 216
Based on the above information, the calculation is as follows
So,
= 432m^3
