Answer:
10.3
Step-by-step explanation:
hope this helps, if any genius answers as well, give brainliest to them
5y² + 2xy – 20x - 100
Step-by-step explanation:
Assume that the distance between City A and City B is <em>x</em> miles,
& the speed of the plane from City A to B is<em> y </em>mph;
The return trip is 20 mph slower so the plane's speed is <em>(y – 20)</em> mph
Since <em>time = distance/speed;</em> The time taken by the plane from City A to B is <em>x / y</em> hrs.
The time taken in return flight is;
<em>x / (y - 20)</em> hrs
The layover was 5hrs long. Therefore the total time taken on the who return trip journey is;
x/y + x/(y-20) + 5
multiply each individual fraction with the LCM of the denominators
x(y-20) + xy + 5 y(y-20)
xy -20x +xy + 5y² – 100
5y² + 2xy – 20x - 100
Answer:
2×2×3×7
Step-by-step explanation:
84 is even, so divisible by 2. 84 = 2×42
42 is even, so divisible by 2. 82 = 2×2×21
21 has a sum of digits of 3, so is divisible by 3. 84 = 2×2×3×7
Answer:
d = 40/7
Step-by-step explanation:
Solve for d:
0.544444 = 28/(9 d)
0.544444 = 49/90:
49/90 = 28/(9 d)
49/90 = 28/(9 d) is equivalent to 28/(9 d) = 49/90:
28/(9 d) = 49/90
Take the reciprocal of both sides:
(9 d)/28 = 90/49
Multiply both sides by 28/9:
Answer: d = 40/7
The time that each car traveled.