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Yanka [14]
2 years ago
15

9 more than the quotient of -36 and -4

Mathematics
1 answer:
Elina [12.6K]2 years ago
5 0
The answer is nine. 9
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Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other.
erastovalidia [21]

The Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other is given below.

<h3>What are the proves?</h3>

1.  To know  collinear vectors:

∧ ⁻a ║ ⁻a

If  ⁻b = ∧ ⁻a

then |⁻b| = |∧ ⁻a|

So one can say that  line ⁻b and ⁻a are  collinear.

2.  If ⁻a and ⁻b  are collinear

Assuming |b| length  is  'μ' times of |⁻a |

Then | 'μ' ⁻a| = | 'μ' ⁻a|

So  ⁻b = 'μ' ⁻a

Learn more about vectors  from

brainly.com/question/25705666

#SPJ1

3 0
2 years ago
Who feels to talk
zubka84 [21]

Answer:

I gotcu

The answer is 30.25

Step-by-step explanation:

5.5 divided by 4 equals 1.375

22 times 1.375 equals 30.25

8 0
3 years ago
Bailey ran 1 mile and 14 yards.How many total feet did bailey run?
Slav-nsk [51]

Answer:

D. 5,322

Step-by-step explanation: 5280 feet in 1 mile, 42 feet in 14 yards

6 0
3 years ago
Read 2 more answers
Show work for 125 divided by 7.75
Mazyrski [523]
7.75 ➗ 125 = 0.062


Simplify ➡ 31 / 4


31 over 4 ➗ 125


Then, divide ➡31 over 1 by 125


and it should leave you with the answer 0.062
7 0
2 years ago
2. A square-based tent has the cross-sectional
ollegr [7]

(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

<u>Explanation:</u>

An image is attached for reference.

(a)

In ΔAOB,

sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m

In ΔBGD,

sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

                                  = 1 m + 1.732 m

                                  = 2.732 m

(b)

DF = ?

In ΔAOB,

tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\

According to the figure, OB = GE = 1.733 m

In ΔBGD,

tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m

According to the figure, DE = DG + GE

                                      DE = 1 m + 1.733 m

                                     DE = 2.733 m

Length of the base, DF = 2 X DE

                              DF = 2 X 2.733 m

                               DF = 5.466 m

8 0
3 years ago
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