Answer:
a). m∠AED = 70°
b). x = 10°
Step-by-step explanation:
a). Quadrilateral ABDE is a cyclic quadrilateral.
Therefore, by the theorem of cyclic quadrilateral,
Sum of either pair of opposite angle is 180°
m(∠AED) + m(∠ABD) = 180°
m(∠AED) = 180° - 110°
m(∠AED) = 70°
Since, ∠AED ≅ ∠EAD
Therefore, m∠AED = m∠EAD = 70°
b). By triangle sum theorem in ΔABD,
m∠ABD + m∠BDA + m∠DAB = 180°
110° + 40° + m∠DAB = 180°
m∠DAB = 180° - 150°
m∠DAB = 30°
m∠BAE = m∠EAD + m∠BAD
= 70° + 30° = 100°
By angle sum theorem in ΔACE,
m∠EAC + m∠AEC + m∠ACE = 180°
100° + 70° + x° = 180°
x = 180° - 170°
x = 10°
Answer:
factor of 6 and 5
Step-by-step explanation:
4 + 2h < -3
2h < -7
h < -3.5
x ∈ (-∞, -3.5)
3(x + 7) = 9(x - 1)
3(x) + 3(7) = 9(x) - 9(1)
3x + 21 = 9x - 9
<u>- 3x - 3x </u>
21 = 3x - 9
<u>+ 9 + 9</u>
<u>30</u> = <u>3x</u>
3 3
10 = x