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steposvetlana [31]
2 years ago
12

What is the measure of the largest side of an isosceles acute, if one side is 36

Mathematics
1 answer:
dusya [7]2 years ago
7 0

The measure of the largest side of an isosceles acute triangle with one side of 36 degrees is 72 degrees.

<h3>What is an isosceles triangle?</h3>

A triangle with two sides and angles of equal length and degrees is an isosceles triangle.

Acute Triangle:-

A triangle whose all angels are greater than and less than 90° i.e., all angels are acute is called an acute triangle.

Therefore, all the three angles are less than 90 degrees and two angles are equal.

If one angle is 36 degrees, the other two angles will be 72 degrees each.

If the two angles are 36 degrees each, the last angle will be 108 degrees. 108 degrees is greater than 90 degrees..

Therefore, the angles will be 36°, 36° and 72°.

Hence, the measure of the largest side of an isosceles acute triangle with one side of 36 degrees is 72 degrees.

learn more on isosceles triangle here: brainly.com/question/16063650

#SPJ1

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rational number, real number

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2. Jada fills her aquarium with water.
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Jada fills her aquarium with water at a constant rate of 5cm/minute for 2 minutes. She then stops the water from running for 1 minute. After that, she started to fill the aquarium at a constant rate of 10cm/minute for another 2 minutes. After 5 minutes, she reduces the water running at a rate of 5cm for 2 minutes. After 7 minutes, she turns off the water and the water is at 25cm.

4 0
3 years ago
If PA. = 0.8, PB. = 0.3 and P(A|B) = 0.6, what is P(A and B)
Sergio [31]

Answer:

p(A∩B) = 0.18

Step-by-step explanation:

<u><em>Formula</em></u> :

p\left( A|B\right)  =\frac{p\left( A\cap B\right)  }{p\left( B\right)  }

………………………………

⇒ p(A∩B) = p(B)×p(A/B)

⇒ p(A∩B) = 0.3 × 0.6

                = 0.18

8 0
2 years ago
Someone please help I don’t understand this please
sdas [7]

The fraction of the image in blue with respect to the <em>entire</em> hexagon is \frac{1}{3}.

<h3>Estimation of the ratio of the shaded region area to the entire area</h3>

Initially we proceed to create auxiliar constructions , represented by red line segments, to re-define the hexagon as a sum of standard figures. According to the figure, we find two types of triangles (type-1 and type-2), and the following relationship between the two types:

A_{1} = A_{2} (1)

Where:

  • A_{1} - Area of a type-1 triangle.
  • A_{2} - Area of a type-2 triangle.

The formulae for the area of the shaded region (A_{s}) and the <em>entire</em> hexagon (A_{h}) are, respectively:

<h3>Shaded region</h3>

A_{s} = 2\cdot A_{1} + 4\cdot A_{2} (2)

<h3>Entire hexagon</h3>

A_{h} = 8\cdot A_{1} + 10\cdot A_{2} (3)

And the fraction of the image in blue is:

\frac{A_{s}}{A_{h}} =  \frac{2\cdot A_{1}+4\cdot A_{2}}{8\cdot A_{1}+10\cdot A_{2}}

\frac{A_{s}}{A_{h}} = \frac{6\cdot A}{18\cdot A}

\frac{A_{s}}{A_{h}} = \frac{1}{3}

The fraction of the image in blue with respect to the <em>entire</em> hexagon is \frac{1}{3}. \blacksquare

To learn more on hexagons, we kindly invite to check this verified question: brainly.com/question/4083236

6 0
3 years ago
ASAP DUE SOON
MrRissso [65]

Answer:

See explanation

Step-by-step explanation:

First image with two graphs:

1. This is a function (Yes)

The domain is x\in [-5,5)

The range is y\in (-2,2]

2 (that graph from the third image). This is not a function (No)

The domain of this relation is x\in (-3,5]

The range is y\in (-2,2)

Second image (parabola):

This is a function (Yes)

The domain is x\in (-\infty, \infty)

The range is y\in (-\infty,0]

Fourth image (cubic parabola):

This is a function (Yes)

The domain is x\in (-4,3)

The range is y\in (-2,4)

7 0
4 years ago
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