Answer:
Solution given:
A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm
and
base[b]PR=60cm.
perpendicular [P]= QR
<u>by</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>
<u>h²</u><u>=</u><u>p²</u><u>+</u><u>b²</u>
80²=QR²+60²
QR²=80²-60²
QR=
QR=20
=52.9=53cm
<u>QR</u><u>=</u><u>5</u><u>3</u><u>c</u><u>m</u><u>.</u>
Answer:
B
Step-by-step explanation:
You just count the dots and check the tables.
Answer:
Perimeter: 4 * s
Area: S 2
Diagonal: s 2 \sqrt {2} 2
Area of square when diagonal is given = 1 2 × d 2 \frac {1} {2}\times d^ {2} 21 × d2
Step-by-step explanation:
Answer:
630.
Step-by-step explanation:
<u>Given the following data;</u>
Dimensions for cube = ¼ inches
Volume = 1/64 cubic inches.
For rectangular box;
Length = 2½ = 5/2 inches.
Width = 2¼ = 9/4 inches.
Height = 1¾ = 7/4 inches.
Volume = 315/32 inches
Therefore, to find the amount of cubes;
Substituting into the equation, we have;
Number of cubes = 630
Answer:
≈ 10.63
Step-by-step explanation:
Calculate the distance d using the distance formula
d = 
with (x₁, y₁ ) = P(- 1, - 1) and (x₂, y₂ ) = L(6, - 9)
d = 
= 
= 
=
=
≈ 10.63 ( to the nearest hundredth )