What is the areas of triangle

Over the summer, for every 14 Okra seeds Dana planted, 9 plants grew. If he planted 182 seeds, how many grew into plants?

vova2212 [387]

Simple...

you have: For every 14 seeds that Okra seeds Dana planted 9 of them grew; if he planted 182 seeds..how many grew?

Set up an equation...

$\frac{9}{14} = \frac{x}{182}$

Cross multiply....

14*x=14x

9*182=1638

14x=1638

$\frac{14x}{14} = \frac{1638}{14} =117
$

x=117

This means that, for 182 seeds planted, 117 of them grew to be plants.

Thus, your answer.

3 0

3 years ago

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Sara drives 171 miles on 7.6 gallons of gas. She uses this information to calculate how many miles per gallon she can drive. Usi

vfiekz [6]

171 / 7.6 = 22.5 miles per gallon

22.5 x 12.5 = 281.25 miles she can drive

7 0

2 years ago

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What is the coefficient of the term 53xy ? A. 5 B.1/3 C.5xy D.5/3

svet-max [94.6K]

It is d i did the test and got an a

7 0

3 years ago

Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap

bazaltina [42]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)$

$A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

<em>The circumference of a quarter of circle is equal to</em>

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

6 0

3 years ago

During one month, a homeowner used 500 units of electricity and 100 units of gas for a total cost of $333. The next month, 400 u

Mice21 [21]

Answer: the cost per unit of gas is $0.28

Step-by-step explanation:

Let x represent the cost per unit of electricity.

Let y represent the cost per unit of gas.

During one month, a homeowner used 500 units of electricity and 100 units of gas for a total cost of $333. This is expressed as

500x + 100y = 333 - - - -- - -- - -- -1

The next month, 400 units of electricity and 150 units of gas were used for a total cost of $286. This is expressed as

400x + 150y = 286 - - - - - - - - - --2

Multiplying equation 1 by 400 and equation 2 by 500, it becomes

200000x + 40000y = 133200

200000x + 75000y = 143000

Subtracting, it becomes

- 35000y = - 9800

y = - 9800/- 35000

y = 0.28

Substituting y = 0.28 into equation 2, it becomes

400x + 150 × 0.28 = 286

400x = 286 - 42 = 244

x = 244/400 = 0.61

7 0

3 years ago