All categories

3 years ago

Describe the domain and range of this function

Mathematics

2 answers:

Galina-37 [17]3 years ago

5 0

Answer:

yes I can u means for generating a mi friend them

UkoKoshka [18]3 years ago

5 0

Answer:

<u>According the graph we have:</u>

Domain: set of input values [0, 26]
Range: set of output values [0, 20]
f(18) = 16
f(5) = 2
f(17) = 14

You might be interested in

I’ll give u brainiest pls help me im so lost

Vlad1618 [11]

Answer:

(f o g)(4)=27

Step-by-step explanation:

(f o g)(4)=2x+5

f(g(4))=2x+5

f(4²-2(4)+3)=2x+5

f(16-8+3)=2x+5

f(8+3)=2x+5

f(11)=2x+5

f(11)=2(11)+5

f(11)=22+5

f(11)=27

Therefore, (f o g)(4)=27

3 0

3 years ago

What is 12378 x 129 divided by 67 x 349 plus 18476 divided by 6 x2390

Artist 52 [7]

answer:15,677,068.4

8 0

3 years ago

There are 45 new houses being built in a neighborhood. Last month 1/3 of them were sold. This month 2/5 of the remaining houses

polet [3.4K]

Answer:

total=45

1/3+2/5=11/15

remaining fraction of houses=1-11/15

=4/15

reamaimg houses=4/15×45=12houses

7 0

4 years ago

Find the exact value of cos(sin^-1(-5/13))

son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

$\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}$

$\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}$

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0

3 years ago

1/4 + 1/2 + x = -3/4

Sati [7]

Hi MonkeyJohnny123,

Solution:

= 1/4 + 1/2 + x = -3/4

= 1/4 + 2/4 + x = -3/4

= 3/4 + x = -3/4

= 3/4 + -6/4 = -3/4

Answer:

-6/4

8 0

3 years ago

Read 2 more answers