Answer:
120°
Step-by-step explanation:
Area of a sector is:
A = πr² (θ/360°)
Plugging in values and solving:
49/3 π = π (7)² (θ/360°)
49/3 π = 49π (θ/360°)
1/3 = θ/360°
θ = 120°
First you would distribute the 3. So it would be (3x+6)+14+7x. Since you can’t do anything inside the parentheses, you drop them. Then you’d combine like terms. 3x+7x is 10x, and 14+6 is 20. That would get you your answer, 10x+20
Given :
- CD is the altitude to AB.
A = 65°.
To find :
- the angles in △CBD and △CAD if m∠A = 65°
Solution :
In Right angle △ABC,
we have,
=> ACB = 90°
=> CAB = 65°.
So,
=> ACB + CAB+ZCBA = 180° (By angle sum Property.)
=> 90° + 65° + CBA = 180°
=> 155° +CBA = 180°
=> CBA = 180° - 155°
=> CBA = 25°.
In △CDB,
=> CD is the altitude to AB.
So,
=> CDB = 90°
=> CBD = CBA = 25°.
So,
=> CBD + DCB = 180° (Angle sum Property.)
=> 90° +25° + DCB = 180°
=> 115° + DCB = 180°
=> DCB = 180° - 115°
=> DCB = 65°.
Now, in △ADC,
=> CD is the altitude to AB.
So,
=> ADC = 90°
=> CAD = CAB = 65°.
So,
=> ADC + CAD +DCA = 180° (Angle sum Property.)
=> 90° + 65° + DCA = 180°
=> 155° +DCA = 180°
=> DCA = 180° - 155°
=> DCA = 25°
Hence, we get,
- DCA = 25°
- DCB = 65°
- CDB = 90°
- ACD = 25°
- ADC = 90°.
Answer:
Step-by-step explanation:
