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stiv31 [10]
3 years ago
15

What is the sale price for an item with an original price of 13.99 after applying a discount of 45%?

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
3 0

Answer:

7.69

Step-by-step explanation:

13.99 x 0.45 = 6.2955 or 6.3

13.99 - 6.3 = 7.69

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Estimate : 1) 48% of 8 2) 3% of 119 3) 26% of 32 4) 76% of 280
zaharov [31]
1) 48% of 8=3.84 
2) 3% of 119=3.57
3) 26% of 32=8.32
4) <span>76% of 280=212.8

Hope this helps ya!</span>
7 0
3 years ago
Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.
jek_recluse [69]

Answer:

\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

Step-by-step explanation:

Let X be a set of all students in your class. The set X is the domain. Denote

                                        C(x) -  ' \text{$x $ has a cat}'\\D(x) -  ' \text{$x$ has a dog}'\\F(x) -  ' \text{$x$ has a ferret}'

\mathbf{a)}

Consider the statement '<em>A student in your class has a cat, a dog, and a ferret</em>'. This means that \exists x \in X so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                         \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)

\mathbf{b)}

Consider the statement '<em>All students in your class have a cat, a dog, or a ferret.' </em>This means that \forall x \in X at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                        \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)

\mathbf{c)}

Consider the statement '<em>Some student in your class has a cat and a ferret, but not a dog.' </em>This means that \exists x \in X so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                      \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)

\mathbf{d)}

Consider the statement '<em>No student in your class has a cat, a dog, and a ferret..' </em>This means that \forall x \in X none of  the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)

\mathbf{e)}

Consider the statement '<em> For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.' </em>

This means that for each of the statements C, F and D there is an element from the domain X so that each statement holds true.

We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

           \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

5 0
4 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Points A and B
Maurinko [17]

Answer:

The answer for the question is 11 and 12 I just got a test back and it was correct

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Write the equation of a line in slope intercept form that is parallel to the line y= 1/3x + 5 and passes through (-9, 5)
vladimir2022 [97]
Find the slope of line 1
The equation of line 1 is y = (1/3)x + 5
m = 1/3

Find the slope of line 2
Line 2 is parallel to line 1. Parallel lines have the same number of slope. So the slope of line 2 is 1/3

Find the slope-intercept form of equation, with m = 1/3 and (-9,5)
General formula
y - y₁ = m(x - x₁)

Input the number to the formula
y - y₁ = m(x - x₁)
y - 5 = 1/3(x - (-9))
y - 5 = 1/3 (x + 9)
y - 5 = (1/3)x + 3
y = (1/3)x + 3 + 5
y = (1/3)x + 8

The equation is y = (1/3)x + 8
7 0
4 years ago
What fraction is closest to -1/2
grigory [225]
<span>fraction is closest to -1/2:</span>
\frac{-1}{1} ; \frac{-2}{2} ; \frac{1}{2} &#10;
These are...
5 0
4 years ago
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