Answer:
Cells have many structures inside of them called organelles. These organelles are like the organs in a human and they help the cell stay alive. Each organelle has it's own specific function to help the cell survive. The nucleus of a eukaryotic cell directs the cell's activities and stores DNA.
Explanation:
hope this Helps
Transcription is the transfer of genetic information from DNA to RNA, and it happens in the nucleus. We can automatically rule out B. B is incorrect because it doesn't make sense; how can a process stop before it even begins?
A. I believe this is incorrect because mRNA is involved when the genetic information needs to leave the nucleus. mRNA would take it to a ribosome outside of a nucleus. Since transcription happens in the nucleus, mRNA is irrelevant before it starts.
C. This doesn't really make sense. mRNA carries information from the DNA, but not vice versa (in these early stages).
D. This would make the most sense, since RNA polymerase needs to attach to the promoter on the strand before transcription can begin.
Answer:
Codominant- traits don’t have a clear dominant or recessive
incomplete dominance- the heterozygous condition shows a “blending” or a “middle” condition
Explanation:
In codominance, the traits are expressed equally in the phenotype thus they don't have a clear dominant or recessive state. For example the ABO blood group alleles. The alleles A and B are codominant each being expressed equally.
In incomplete dominance the traits show intermediate expression where one allele expresses itself more strongly than the other. An example in man is seen in the inheritance of the disease sickle cell anaemia. Heterozygote who carry the sickle cell gene are said to have sickle cell trait and as such the carrier allele (HBa) has a stronger influence on the phenotype than the dominant alle (HBs).
Answer:
Please find the punnet square to this question as an attachment
F1 generation:
genotype = BW
Phenotype = Erminette offsprings
F2 generation:
genotype = BB (1): BW(2): WW(1)
Phenotype = 1 Black, 2 Erminette, 1White
Explanation:
This question involves a gene coding for feather color in chickens. The allele for black feathers (B) is codominant with the allele for white feathers (W) to form an erminette chicken (black and white speckles).
According to this question, a cross between a chick with black (BB) feathers and chicken with white (WW) feathers will result in an all erminette chicken (BW) in the F1 generation (see attached image)
Also, in the F2 generation got by self-crossing the Erminette genotype in the F1 generation (BW), the following genotypic and phenotypic ratios are observed:
Genotypic ratio = BB (1): BW(2): WW(1)
Phenotypic ratio = 1 Black, 2 Erminette, 1White
I think the answer would be B. Genealogy.
