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Zigmanuir [339]
3 years ago
11

The benefit of measuring the initial rate of a reaction, V0, is that early in the course of the reaction, A) Km is the substrate

concentration at which V0 = Vmax. B) The rate of product formation is linear and [S] has not been lowered significantly. C) V0 is least responsive to changes in [S]. Km will be lower, so the enzyme will bind S better. D) V0 will be independent of enzyme concentration.
Biology
1 answer:
aleksandr82 [10.1K]3 years ago
4 0

Answer:

Rate of product formation is linear and [S] has not been lowered significantly.

Explanation:

The rate of enzyme-catalyzed reactions is affected by several factors, the contraction of substrates [S] is one of them. The substrate concentration keeps on changing as the reaction proceeds. This is why the reaction rate is measured at the initial stages of reactions when the substrate concentration [S] is much greater than the concentration of the enzyme. It is called the initial rate or initial velocity.

Under the conditions of higher substrate concentration and relatively much lower enzyme concentrations, only a few molecules of substrates are being converted into product. At a relatively higher substrate concentration, the rate of product formation increases linearly.

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Using the product rule of probability, calculate the odds of getting an individual that receives the bb genotype and therefore s
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B) 1/2 X 1/2 = 1/4

Explanation:

It happens when both the parents are heterozygous for the trait. The cross related to this result is shown as under:

                          Father           Mother

                             Bb       x        Bb

                             /   \                 /   \

Gametes:           B      b            B      b

                          |        |              |       |

Probability:      1/2     1/2          1/2    1/2

The probability of formation of 'b' gamete from father is 1/2 because there are only two gametes 'B' and 'b' and out of these two one will be assorted as 'B' and another one as 'b' and from mother also the probability of formation of 'b' gamete is 1/2.

Now the assortment of gametes with each other is an independent event i.e. any gamete from father can fuse with any gamete of mother so the overall probability of formation of 'bb' genotype will be 1/2 x 1/2 = 1/4.

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3 years ago
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