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klio [65]
3 years ago
7

If A and B are independent events with P( A) = 0.60 and P( A| B) = 0.60, then P( B) is: a. 0.60 b. cannot be determined with the

information given c. 0.36 d. 1.2
Mathematics
1 answer:
Simora [160]3 years ago
7 0

Answer:

<h2>B. cannot be determined</h2>

Step-by-step explanation:

For two events A and B to be independent, it means they can occur at the same time i.e the occurrence of one does not affect the other occurring. It is represented as P(A∩B) = P(A)P(B)

Given P( A) = 0.60 and P( A| B) = 0.60, to find P(B), we will use the formula for the conditional probability P( A| B) = P(A∩B) /P(B)

P( A| B) = P(A)P(B) /P(B)

P( A| B) = P(A)

Since  P( A| B) = 0.60, therefore P(A) is also equal to 0.60 and P(B) cannot be determined since they cancelled out already

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Answer:

The height of this cube-shaped water tank is 35 m.

Step-by-step explanation:

The formula for the volume of a cube of side length s is V = s^3.

Here V = s^3 = 42,875 m^3.

Taking the cube root of both sides, we obtain the side length, s:

s = ∛(42,875 m^3) = 35 m

The height of this cube-shaped water tank is 35 m.

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The South Memorial School is designing a new playground. There will be a walkway that diagonally crosses the square playground.
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2 years ago
Area of a triangle with points at (-9,5), (6,10), and (2,-10)
Ann [662]
First we are going to draw the triangle using the given coordinates. 
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
d_{AB}= \sqrt{(6+9)^2+(10-5)^2}
d_{AB}= \sqrt{(15)^2+(5)^2}
d_{AB}= \sqrt{225+25}
d_{AB}= \sqrt{250}
d_{AB}=15.81

Distance from point A to point C:
d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}
d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}
d_{AC}= \sqrt{11^2+(-15)^2}
d_{AC}= \sqrt{121+225}
d_{AC}= \sqrt{346}
d_{AC}= 18.60

Distance from point B from point C
d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}
d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
d_{BC}= \sqrt{416}
d_{BC}=20.40

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
s= \frac{54.81}{2}
s=27.41

Finally, to find the area of our triangle, we are going to use Heron's formula:
A= \sqrt{s(s-AB)(s-AC)(s-BC)}
A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
A= \sqrt{27.41(11.6)(8.81)(7.01)}
A=140.13

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0
2 years ago
What is the nth term rule of the quadratic sequence below?<br> 8,14,22,32 ,44, 58, 74...
DanielleElmas [232]

Answer:

y=n^2+3n+4

Step-by-step explanation:

Sequence,S: 8,14,22,32 ,44, 58, 74...

First differences of S: 6,8,10,12,14,16,...

Second differences of S: 2,2,2,2,2,2,....

It is indeed a quadratic since the 1st differences that are the same are the second differences.

So the 1st term is 8. If the 0th term was listes it would be 4 since 8-4=4 and 6-4=2.

This means our quadratic it is in the form

y=an^2+bn+c where c=4.

So we have y=an^2+bn+4.

Now we can find a and b using two points from our sequence to form a system of equations to solve.

(1,8) gives us 8=a(1)^2+b(1)+4

Simplifying gives 8=a+b+4

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(2,14) gives us 14=a(2)^2+b(2)+4

Simplifying gives 14=4a+2b+4

Subtracting 4 on both sides gives 10=4a+2b

So we have the following system to solve:

4=a+b

10=4a+2b

I'm going to solve using elimination/linear combination style.

Dividing second equation by 2 gives the system as:

4=a+b

5=2a+b

Subtract the 2nd equation from the first gives:

-1=-1a

This implies a=1 since -1=-1(1) is true.

If a+b=4 and a=1, then b=3. Because 3+1=4.

So the equation is y=1n^2+3n+4 or y=n^2+3n+4.

8 0
2 years ago
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