A blue billiard ball with mass m crashes into a red billiard ball with the same mass that is at rest. The collision results in t
he blue billiard ball traveling with a velocity of v and the red billiard ball travelling with a velocity of 3v. In terms of v and m, determine the blue billiard ball’s velocity before the collision...
1 answer:
Draw a diagram to illustrate the problem as shown below.
Each ball has mass = m.
The initial velocity of the blue ball = u.
The initial velocity of the red ball = 0.
Initial total momentum is
P1 = m*u + m*0 = mu
Final momentum is
P2 = mv + 3mv = 4mv
Because momentum is conserved,
mu = 4mv
u = 4v
Answer:
The velocity of the blue ball before the collision is 4v.
Each ball has mass = m.
The initial velocity of the blue ball = u.
The initial velocity of the red ball = 0.
Initial total momentum is
P1 = m*u + m*0 = mu
Final momentum is
P2 = mv + 3mv = 4mv
Because momentum is conserved,
mu = 4mv
u = 4v
Answer:
The velocity of the blue ball before the collision is 4v.
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Given:
Point is T(-3,8).
To find:
The coordinates of T' after .
Solution:
We know that, means the figure reflected across the x-axis then reflected across y-axis.
If a figure reflected across x-axis, then
If a figure reflected across y-axis, then
Therefore, the required point is T'(3,-8).