A blue billiard ball with mass m crashes into a red billiard ball with the same mass that is at rest. The collision results in t
he blue billiard ball traveling with a velocity of v and the red billiard ball travelling with a velocity of 3v. In terms of v and m, determine the blue billiard ball’s velocity before the collision...
1 answer:
Draw a diagram to illustrate the problem as shown below.
Each ball has mass = m.
The initial velocity of the blue ball = u.
The initial velocity of the red ball = 0.
Initial total momentum is
P1 = m*u + m*0 = mu
Final momentum is
P2 = mv + 3mv = 4mv
Because momentum is conserved,
mu = 4mv
u = 4v
Answer:
The velocity of the blue ball before the collision is 4v.
Each ball has mass = m.
The initial velocity of the blue ball = u.
The initial velocity of the red ball = 0.
Initial total momentum is
P1 = m*u + m*0 = mu
Final momentum is
P2 = mv + 3mv = 4mv
Because momentum is conserved,
mu = 4mv
u = 4v
Answer:
The velocity of the blue ball before the collision is 4v.
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Answer:
Step-by-step explanation:
Remark
Always the easiest way to study these questions is to get a graph. The one below shows
Red: y = x^2
Blue: y= 3(x + 1)^2
You will notice that (x+1)^2 shifts the graph Left -- the opposite to what you might think.
The 3 is a little harder. It narrows the red mother graph. Which choice says that?
The choice is between b and d. Why. Because the blue graph is to the left of the red one.
You have to learn the meaning of compressed. A better word might be narrows.
Answer
B
