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RideAnS [48]
4 years ago
11

A right triangle is removed from a rectangle as shown in the figure. Find the area of the remaining part of the rectangle. [Area

of a triangle = 1/2(b)(h)]
Mathematics
1 answer:
OlgaM077 [116]4 years ago
4 0
I recently answered this question. I found the same problem with its corresponding image.

The rectangle has a length of 8 inches and width of 6 inches.
The right triangle was taken from the width. Its short leg measures 2 inches and the remainder of the width was 2 inches.

Area of the rectangle = Length x Width
A = 8 inches * 6 inches
A = 48 square inches.

Area of a right triangle = 1/2 a h
a is the short leg = 2 inches
h is the long leg = width - remainder of the width = 6 in. - 2 in. = 4 inches.

Area = 1/2 * 2 in. * 4in.
Area = (1*2*4)/2
A = 8/2
A = 4 square inches.

Area of Rectangle - Area of Triangle = Area of remaining figure.

<span>48 sq. in - 4 sq. in. = 44 sq. inches.</span>

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Two trains leave a town at the same time heading in opposite directions. One train is traveling 12 mph faster than the other. Af
vichka [17]

Answer:

Step-by-step explanation:

I'm going to paint you a picture in words of what this looks like on paper.  We have a train leaving from a point on your paper heading straight west.  We have another train leaving from the same point on your paper heading straight east.  This is the "opposite directions" that your problem gives you.  

Now let's make a table:

                 distance       =        rate      *       time

Train 1

Train 2

We will fill in this table from the info in the problem then refer back to our drawing.  It says that one train is traveling 12 mph faster than the other train.  We don't know how fast "the other train" is going, so let's call that rate r.  If the first train is travelin 12 mph faster, that rate is r + 12.  Let's put that into the table

               distance        =        rate        *        time

Train 1                                        r

Train 2                                    (r + 12)

Then it says "after 2 hours", so the time for both trains is 2 hours:

           

               distance        =        rate        *        time

Train 1                                        r           *          2

Train 2                                  (r + 12)       *          2

Since distance = rate * time, the distance (or length of the arrow pointing straight west) for Train 1 is 2r.  The distance (or length of the arrow pointing straight east) for Train 2 is 2(r + 12) which is 2r + 24.  The distance between them (which is also the length of the whole entire arrow) is 232.  Thus:

2r + 2r + 24 = 232 and

4r = 208 so

r = 52

This means that Train 1 is traveling 52 mph and Train 2 is traveling 12 miles per hour faster than that at 64 mph

5 0
3 years ago
Read 2 more answers
Please help soon!! I will give brainliest to the first correct answer!
Sladkaya [172]

Answer:

1(left) goes with 1

2(left)  goes with 3

3(left) goes with 2

4(left) goes with 4

Step-by-step explanation:

2(5+6) = 22


3(5+3) = 24


2(4+5) = 18


2(3+2) = 10  

10 + 12 = 22  

8+ 10 = 18


15 + 9 = 24


6 + 4 = 10

1(left) goes with 1

2(left)  goes with 3

3(left) goes with 2

4(left) goes with 4

5 0
3 years ago
Read 2 more answers
Help The question is in the picture ( PS. This is part two from my latest post)
meriva

Answer:

100

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Hay dos veces la cantidad de manzanas que naranjas en un puesto de frutas. Después de que se vendieron 15 naranjas, hay tres vec
Elan Coil [88]

There are 45 oranges and 90 apples in the beginning.

Step-by-step explanation:

Let the no. of orange be 'b'

Let the no. of apples be 'a'

Given that,

2b = a

3(b-15) = a

3b - 45 = a

3b - 45 = 2b

3b - 2b = 45

b = 45

2b = a

2(45) = a

a = 90

There are 45 oranges and 90 apples in the beginning.

4 0
3 years ago
Look at the proof. Name the postulate you would use to prove the two triangles are congruent.
Georgia [21]
Congruency is made up of two factors:
1) they possess the same angles
2) they possess the same side lengths, pertaining to each angle.
8 0
3 years ago
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