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3 years ago

13

How do you find the prime factorization of 504

1 answer:

arlik [135]3 years ago

6 0

1 x 2 x 2 x 2 x 3 x 3 x 7

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4. Multiply: 3x2(4x3 - 2x2 + 7x - 4)

jeka57 [31]

Answer:

-120

Step-by-step explanation:

4 0

3 years ago

Use the distributive property to simplify -8(5x-3)

Alexxandr [17]

Answer:

$-40x+24$

Step-by-step explanation:

Use distributive property.

$-8(5x-3)\\\rightarrow -8 * 5x = -40x\\\rightarrow -8*-3= 24\\\\\text {So: }-8(5x-3) \rightarrow -40x+24$

6 0

4 years ago

Read 2 more answers

Which of the following are polynomial expressions

Sonja [21]

Answer:

1, 3 and 5.

Step-by-step explanation:

4 0

3 years ago

Bezzdna [24]

Answer:

$y=-\dfrac{9}{40}x^2+\dfrac{441}{40}\\ \\y=-\dfrac{9}{160}x^2+\dfrac{1,521}{160}$

Step-by-step explanation:

If a parabola has its vertex on the y-axis, then its equation is

$y=ax^2+b$

This parabola passes through the point R(3,9), then

$9=a\cdot 3^2+b\\ \\9=9a+b$

The area of the right triangle PQR is

$A_{PQR}=\dfrac{1}{2}\cdot PQ\cdot QR$

Find PQ and QR, if $P(x_1,0),\ Q(3,0),\ R(3,9):$

$PQ=\sqrt{(x_1-3)^2+(0-0)^2}=|x_1-3|\\\\QR=\sqrt{(3-3)^2+(0-9)^2}=9$

Now,

$40.5=\dfrac{1}{2}\cdot |x_1-3|\cdot 9\\ \\90=9|x_1-3|\\ \\|x_1-3|=10\\ \\x_1-3=10\ \text{or}\ x_1-3=-10\\ \\x_1=13\ \text{or }x_1=-7$

We get two possible points $P_1(-7,0)$ and $P_2(13,0).$

For point $P_1:\\$

$0=a\cdot (-7)^2+b\\ \\49a+b=0$

So,

$b=-49a\\ \\9=9a-49a\\ \\-40a=9\\ \\a=-\dfrac{9}{40}\\ \\b=\dfrac{441}{40}\\ \\y=-\dfrac{9}{40}x^2+\dfrac{441}{40}$

For point $P_2:\\$

$0=a\cdot (13)^2+b\\ \\169a+b=0$

So,

$b=-169a\\ \\9=9a-169a\\ \\-160a=9\\ \\a=-\dfrac{9}{160}\\ \\b=\dfrac{1,521}{160}\\ \\y=-\dfrac{9}{160}x^2+\dfrac{1,521}{160}$

5 0

3 years ago

Which expression has the largest value? Each has 9/16 as a factor.

Anvisha [2.4K]

Answer:

A

Step-by-step explanation:

5 0

3 years ago