Question

What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K?

Answer 1

Answer:

Pressure, P = 28.2 kPa

Explanation:

Given that,

Number of moles, n = 0.54 mol

Volume of ideal gas, V = 35.5 L

Temperature, T = 223 K

We need to find the pressure of ideal gas. The equation of ideal gas is given by :

$PV=nRT$

R is gas constant

P is pressure

$P=\dfrac{nRT}{V}\\\\P=\dfrac{0.54\ mol\times 8.314\ kPa- L/mol- K\times 223\ K}{35.5\ L}\\\\P=28.2\ kPa$

So, the pressure of the gas is 28.2 kPa.                              

Answer 2

Answer:

28.2

Explanation:

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