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Answer:



Step-by-step explanation:
Required
Find x
(a)
x is calculated using tangent formula

Make x the subject



--- approximated
(b):
x is calculated using cosine formula

Make x the subject



(c):
x is calculated using sine formula

Make x the subject



--- approximated
Answer:
f(x) = |x|+48 would make the vertex be (0,48)
Step-by-step explanation:
Since the y-coordinate changed, this means that only vertical shift could have occured. Therefore, 48 must've been added to |x|.
Answer:

Step-by-step explanation:
Assuming the given logarithmic equation is

We interchange x and y to get:

We solve for y now:

We add 4 to both sides to get;

Divide through by 4:

Answer:
A)segment A"B"= AB / 2
Step-by-step explanation:
Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. Which equation explains the relationship between segment AB and segment A"B"?
coordinate plane with triangle ABC at A(-3, 3), B(1, -3), and C(-3, -3)
A)segment A"B"= AB / 2
B)segment AB = segment A"B"/ 2
C)segment AB / segment A"B"= 1/2
D)segment A"B" / segment AB = 2
A"B" = AB / 2
Because
1. translations do not change the lengths of segments, so (x+2, y+0) preserves the length of AB, i.e. mA'B' = mAB
2. Dilation causes the new segment to be transformed to a new length according to the old length * the scale factor of (1/2).
Therefore A"B" = (1/2)AB, or AB/2.