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m_a_m_a [10]
4 years ago
5

In a candy bar, 165 calories are from sugar. There are 250 calories in the candy bar. What percent of the calories are from suga

r?
Mathematics
2 answers:
icang [17]4 years ago
4 0
You can simply find out the percentage of the calories from the sugar with this formula :

165/250 x 100% 

You will find out that the percentage would be 66 %

hope this helps


mixas84 [53]4 years ago
4 0

Answer:

66% of the calories are from sugar.

Step-by-step explanation:

We have been given that

Out of 250 calories in the candy bar, 165 calories are from sugar.

Thus, the percent of the calories are from sugar is given by

\%=\frac{\text{Calories of sugar}}{\text{Total calories}}\times100\\\\\%=\frac{165}{250}\times100\\\\\%=66\%

Therefore, 66% of the calories are from sugar.

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(2 points) Consider the linear system y⃗ ′=[−35−23]y⃗ . Find the eigenvalues and eigenvectors for the coefficient matrix. ????1=
oksian1 [2.3K]

Answer:

Please see the attached file for the complete answer.

Step-by-step explanation:

Download pdf
6 0
3 years ago
4n+1=25<br>Please help with an explanation ​
dlinn [17]

Answer:

n = 6

Step-by-step explanation:

To isolate n, subtract 1 from both sides:

4n + 1 = 25

4n = 24

Then divide by 4 on both sides:

4n = 24

n = 6

Hope this helped :)

4 0
3 years ago
Read 2 more answers
Can any one help me in this please any math genius
andriy [413]
It is 10 to 1 significant figures
3 0
3 years ago
Find the area of the shaded region. round answers to the nearest tenth. assume all inscribed polygons are regular. 29.3 units2
FromTheMoon [43]
The picture in the attached figure

we know that
the area of the shaded region is equal to
(2/3)*[area of the circle - the area of the triangle]  

step 1
Find the area of a circle Ac
Ac = π r²
Ac = π (6)²
Ac = 113.10 units²

step 2
find the area of the triangle At
The triangle is an equilateral triangle with angles on each corner equal to 60 degrees. Meanwhile,
the 3 angles at the center is 120 degrees each since a circle is 360 degree.
 We know that the radius (line from centerpoint to corner) is equivalent to 6.
Using the cosine law,
we can calculate for the length of one side.
s² = 6^ + 6² – 2 (6) (6) cos 120
s² = 108
s = 10.4 units
Since this is an equilateral triangle, therefore, all sides are equal.
The area for this is:
At = (sqrt3 / 4) * s²
At = 46.77 units²

step 3
the area of the shaded region=(2/3)*[area of the circle - the area of the triangle]  
the area of the shaded region=(2/3)*[113.10-46.77]------> 44.22 units²

therefore

the answer is
the area of the shaded region is 44.22 units²


5 0
3 years ago
help please! Darren is finding the equation in the form y = m x + b for a trend line that passes through the points (2, 18) and
andrezito [222]

Answer:  d) 14

Step-by-step explanation:

Equation of a line passing through (a,b) and (c,d):

(y-b)=\dfrac{d-b}{c-a}(x-a)

Equation of a line passing through (2, 18) and (–3, 8):

(y-18)=\dfrac{8-18}{-3-2}(x-2)\\\\\Rightarrow\ (y-18)=\dfrac{-10}{-5}(x-2)\\\\\Rightarrow\ (y-18)=2(x-2)\\\\\Rightarrow\ y-18=2x-4\\\\\Rightarrow\ y=2x-4+18\\\\\Rightarrow\ y=2x+14

Comparing resulting equation y=2x+14 to y = m x + b, we get value of b= 14.

Hence, correct option is d) 14

6 0
3 years ago
Read 2 more answers
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