You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
Step-by-step explanation:
hope this helps
Answer:
A
Step-by-step explanation:
given 
= 
using the method of cross- multiplication then
8P = 42 ( divide both sides by 8 )
P = 
= 5.25
Y= -2/6 +4 theyre decreasing because the slope is negative
Answer:
<h2>thank you me and brainiest me</h2>
Step-by-step explanation:
Polynomial equation Solving for 8x + 24 = 0
standard form:8(x + 3) =0
Factorization:
8(x + 3) = 0
solutions
x = −24
8
= −3
9514 1404 393
Answer:
a ≈ 4.68
Step-by-step explanation:
The law of cosines tells you ...
a² = b² +c² -2bc·cos(A)
a = √(b² +c² -2bc·cos(A))
a = √(5² +8² -2·5·8·cos(33°)) = √(25 +64 -80·0.83867) ≈ √21.906
a ≈ 4.68
