im not sure this is right
g'(x) = 6b(-5x + 1)^5 (-5)
g'(x) = -30b(-5x +1)^5
g''(x) = -30b(5)(-5x + 1)^4 (-5)
g''(x) = 750b (-5x +1)^4
g(x) = b(−5x + 1)6 − a
when
g(-x) = b(5x +1)6 - a
g'(x) = -30b(-5x +1)^5 = 0
-5x +1 = 0
x = 15
Answer:
um
Step-by-step explanation:
Answer:
1/6
Step-by-step explanation:
A subsidiary or intermediate theorem in an argument or proof.
Source: Wikipedia
