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OLEGan [10]
3 years ago
8

F(x)=3x^2-36 find x

Mathematics
1 answer:
VLD [36.1K]3 years ago
5 0
I got (B) 
But wait until someone else answers
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Physical quantities are identified uniquely by
bezimeni [28]

Answer:

The correct answer is units.

Step-by-step explanation:

A physical quantity must have a determined unit so it has a numerical value assigned to it. A unit is a standardized way to relegate a numerical amount to properties of a specific measurement. For instance, the meter (m), second (s), and kilogram (kg) are specific units that permit us to relegate numbers to estimations of length, time, and mass measurements.

3 0
3 years ago
Julie ran a race 2 minutes faster then Teri did. If Julie ran the race in 28 mins, which equation can be used to find the number
Lynna [10]

Answer:(28)+2

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Help plz:)))I’ll mark u Brainliest
goldfiish [28.3K]

Answer:

11, 21, 31

Step-by-step explanation:

In a triangle with side lengths a, b, and c, any two sides must have a sum larger than the third.

Using this rule, the possible side lengths out of these choices that could form a triangle are:

21,

11,

31

8 0
2 years ago
The line graphed below has a slope of ____.<br><br> 3<br> 1/3<br> -3
Scilla [17]
It is -3 because it had a negative slope
5 0
2 years ago
Read 2 more answers
The right end of a relaxed standard spring is at the origin; the left end is clamped at some point on the negative x-axis. Holdi
ella [17]

The work required to stretch the spring is 350J.

<h3>Hooke's Law</h3>

This law can be written by the formula: F=kx, where:

F= elastic force (N)

k= spring constant (N/m)

x= linear displacement (m)

<h3>Spring Work</h3>

For finding the spring work in J, you should apply the formula  W=\frac{k*(\Delta x)^2}{2}, where:

W= work (J)

k= spring constant (N/m)

x= difference between the linear displacements (m)

The question gives:

x=5 cm=0.05m requires a force of 1.4N

x=8 cm =0.08m

  • Step 1 - First, you should find the spring constant from Hooke's law, for x=5 cm and F=1.4N.

                                          F=kx\\ 1.4=k*0.05\\ \\ k=\frac{1.4}{0.05} =28\frac{N}{m}

  • Step 2 - Now you can apply the formula for spring work.

                                       W=\frac{k*(\Delta x)^2}{2}\\ \\ W=\frac{28*(8-3)^2}{2} \\ \\ W=\frac{28*(5)^2}{2}\\ \\  W=\frac{28*25}{2}\\ \\  W=\frac{700}{2}=350J

Read more about the spring work here:

brainly.com/question/3317535

5 0
2 years ago
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